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krishan
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krishan
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Hi krishan,

We can use this approach:

At least 1 heart = 1 -P (No Hearts) = 1- (39C5/52C5)

Will give same result.
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krishan
HI, is there a simple way to solve the question below:

What is the probability of getting at least one heart in a 5-card hand dealt from a standard 52-card deck?

My approach was to calculate it as:

At least 1 heart = 1 - No Hearts, which implies

At least 1 heart = 1 -39/52 x 36/51 x 35/50 x 34/49 x 33/48

any simpler approach?

Thanks


there isn't a simpler one!! :lol:

'at least 1' questions are best solve with the 1-no approach



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