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Quant Question of the Day 11 members online out of 121615
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Thank you
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Data Sufficiency Butler: April 2024
April 15DS 1DS 2
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Problem Solving Butler: April 2023
April 15PS 1PS 2
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Yes!!
Thanks
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hey, here shouldn’t the ans be 10,000(0.8)^9? Is there something Im missing?

Screenshot 2024-04-15 151542.png

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Nidhi1715 wrote:
hey, here shouldn’t the ans be 10,000(0.8)^9? Is there something Im missing?

in thousands of $
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sneaky questions
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­A certain machine, which had an original value of $10,000 when purchased new, depreciated in value each year for 9 years. For each year after the machine was purchased, its value was at most 80 percent of its value the previous year. What was the maximum possible value, in thousands of dollars, of the machine 9 years after it was purchased?

A. \((10*0.8)^8\)
B. \((10*0.8)^9\)
C. \(10(0.8)^8\)
D. \(10(0.8)^9\)
E. \(10(0.8)^{10}\)


To find the maximum possible value, let’s assume the value of the machine was exactly 80% of its value from the previous year, not less. Then, its value in 9 years would be $10,000 * 0.8^9. However, note that the question asks for the value in thousands of dollars. Therefore, expressed in thousands of dollars, the value is 10 * 0.8^9.

Answer: D.­­­
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Hi guys! Can anyone help explain how they got to right answer here for these two overlapping set questions? My approach is the matrix but I can’t seem to get to the right answer. This is OG Practice Exam

Screenshot 2024-04-15 at 11.08.09 PM.png

Screenshot 2024-04-15 at 11.00.23 PM.png

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dabaoruwariye wrote:
Hi guys! Can anyone help explain how they got to right answer here for these two overlapping set questions? My approach is the matrix but I can’t seem to get to the right answer. This is OG Practice Exam

For the second one
Use the Venn diagram

N=400
Given a watch =260
Given a phone 80
Given both X = 1/2 Y
Neither received any of =Y

400= (260-1/2Y) + (80-1/2Y) -(1/2Y)+Y
340+1/2Y=400
1/2Y=60

We want to find how many received only what (260-1/2Y)
The 260-1/2Y=260-60=200
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dabaoruwariye wrote:
Hi guys! Can anyone help explain how they got to right answer here for these two overlapping set questions? My approach is the matrix but I can’t seem to get to the right answer. This is OG Practice Exam

Any idea for the 1st one
By using the Venn diagram
How to arrive at the possible n interval

171 stores(90percent)
76 stores that rent
Y store that do both

We will find Ymax and Y min
Ymin = 247-190=57
Ymax has to be less than the lesser value (76 stores)
57<= Y<=76
How to conclude for n
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thanks, not sure where the 247 came from
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Here is my take on the first question.
First -> the max limit of n
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Quant1_16Apr.png

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Next -> The min limit of n
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Quant2_16Apr.png

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Multiple ways of solving the question. This is one :)
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Question 2 - I think the answer should be 200.
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Hope this helps.
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Screenshot 2024-04-16 at 12.10.28 PM.png

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What should be the correct approach here
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pranavkohli16 wrote:
What should be the correct approach here

Maybe this will help.
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Quant3_16Apr.png

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That said, I think this one is already covered in a GC thread. This should help ->

https://gmatclub.com/forum/the-chart-ab ... 20058.html
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This question is discussed in detail here: https://gmatclub.com/forum/the-chart-ab ... 20058.html
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The chart above shows political and geographic data on a certain legislative committee of 20 members, each of whom belongs to 1 of 2 political parties and lives in 1 of 4 regions. How many subcommittees of this legislative committee are possible that contain exactly 1 member from each of the 4 regions and the same number of members from each of the 2 political parties?

A. 10
B. 20
C. 99
D. 246
E. 495


Deconstructing the wording, we find that we need subcommittees with one member from each of the four regions, resulting in exactly four members, of which two are from Party A and two from Party B.

Since Party B has fewer members and they reside in fewer regions, let’s construct the subcommittees starting with Party B first. As Party B must delegate one member from each region it is represented in, we have the following scenarios for Party B’s delegation:

    1. From North and South;
    2. From North and East;
    3. From South and East.

Let’s count the possibilities:

1. Party B delegates one member from North and South: this can be done in 2*4 = 8 ways. In this case, Party A should delegate from West and East: this can be done in 3*2 = 6 ways. Total for this case = 8*6 = 48;

2. Party B delegates one member from North and East: this can be done in 2*3 = 6 ways. In this case, Party A should delegate from South and West: this can be one in 1*3 = 3 ways. Total for this case = 6*3 = 18;

3. Party B delegates one member from South and East: this can be done in 4*3 = 12 ways. In this case, Party A should delegate from North and West: this can be done in 5*3 = 15 ways. Total for this case = 12*15 = 180.

Total = 48 + 18 + 180 = 246.

Answer: D.­
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Data Sufficiency Butler: April 2024
April 16DS 1DS 2
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Problem Solving Butler: April 2023
April 16PS 1PS 2
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hi guys, how do we solve this?
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guys can you please
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follow me
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Screenshot (2).png

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U can assume easy values to solve this.
Let’s say, brand B costs 100 rupees and mileage is 10km. Per km cost is 10 rupees
Brand A will cost 150 rupees and mileage will be 25 km. Per km cost will be 6 rupees.
So 40% less cost
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Hi , Is there anywhere for free where I can practice topic wise quant other than overall mocks. Any separate topic wise test options ?
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srijasinha wrote:
Hi , Is there anywhere for free where I can practice topic wise quant other than overall mocks. Any separate topic wise test options ?

You can use forum quiz for that.
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what is the remainder when (12^91 + 14^91) is divided by 169?
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0? (what I got!). Happy to be corrected if I messed up somewhere.
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12?
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2^91??
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26?
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Sorry the remainder I took for the 12 91 and 14 91 was wrong the answer should be 2
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Hmm. We all got different answers. Hope Rahul shares the official answer soon! :)
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Quant4_16Apr.png

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ratpat wrote:
U can assume easy values to solve this. Let’s say, brand B costs 100 rupees and mileage is 10km. Per km cost is 10 rupees Brand A will cost 150 rupees and mileage will be 25 km. Per km cost will be 6 rupees. So 40% less cost

40%, easy with plug ins
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My solving of this one. I am not sure gmat typically tests binomial expansion though.
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it has a basic trick like (a-b)^3 + (a+b)^3 = a3 + a3 = 2 a3. similarly (13-1)^91 & (13+1)^91 has odd powers, so only 13^x numbers will remain. where x < 2, so 13^x /13^2 will leave 0 as x >2.
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same
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Quick DS question:
Is z even?
1) 3z = even
2) 5z = even
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T4Star wrote:
Quick DS question: Is z even? 1) 3z = even 2) 5z = even

Odd*even= even
3*z=even; 5*z=even

3and 5 are odd
For the product to be even Z must be even
Answer D

It isn’t the appropriate group
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Added a question on the DS forum :)
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Edoua wrote:
Odd*even= even 3*z=even; 5*z=even 3and 5 are odd For the product to be even Z must be even Answer D It isn’t the appropriate group

Z can be a fraction too...
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T4Star wrote:
Z can be a fraction too...

True
Sorry I missed
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T4Star wrote:
Z can be a fraction too...

But for the product to be even, Z must be even
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Edoua wrote:
But for the product to be even, Z must be even

True. Only way to reach the conclusion is by keeping Z as an even integer.
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T4Star wrote:
Quick DS question:
Is z even?
1) 3z = even
2) 5z = even

­The answer is C, not D because we are don’t know whether z is an integer when evaluating the options individually. This question is discussed here: 

https://gmatclub.com/forum/is-z-even-1- ... 13535.html

Hope this helps.
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Data Sufficiency Butler: April 2024
April 17DS 1DS 2
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Problem Solving Butler: April 2023
April 17PS 1PS 2
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Hi, I wanted to ask, is doing the OG, Quant Review and giving all of the Gmat Club Quant practice tests enough practice for the quant section??
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anyone??
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oneinabillion wrote:
Hi, I wanted to ask, is doing the OG, Quant Review and giving all of the Gmat Club Quant practice tests enough practice for the quant section??

Yes it is.
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okay thanks
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Can someone help pls with this ques

1.JPG

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I guess you forgot to subtract both AB and RH- .
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4 + 17 - 1
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4+ 17-1 (because that one person who is AB and has RH -ve is double counted)!
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don’t even know where to start solving this ques

2.JPG

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Range of a function mean what all values can f(x) be. As it is X squared, and we are given "for all real numbers", lets say X is 0. Then f(0) = 1. Now on either side of zero no matter the value of x, squaring makes it positive. So 1/value greater than 1. That means, f(x) can be less than or equal to 1.
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The first step to solving is to understand what is given and what is asked.

We are given a certain function (1/(x2+1)). We are being asked - what all values can (1/(x2+1)) take?

Whatever the value of x, x2 has to be >=0.

- If x =0, then x2 is 0
- If x is negative or positive, then x2 is positive.

So, (1/(x2+1)) is either 1 (when x =0, (1/(x2+1)) = 1/1 = 1) or a positive fraction (greater than o, lesser than 1). Example - x = -3, (1/(x2+1)) = 1 /10 = 0.1

In essence, whatever the value of x, (1/(x2+1)) has a "range" 0<x <=1 (positive, real numbers <=1). So, choice E.
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100 people question is discussed here: https://gmatclub.com/forum/the-table-ab ... 17244.html
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Ah. Apologies for the typo. I meant 0 < (1/(x2+1)) <= 1. Guess it was still clear!
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The "range" question is discussed here: https://gmatclub.com/forum/the-range-of ... 17079.html
Hope this helps.
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Q: When integer k^4 is divided by 32 the remainder is zero. Which of the following could be remainder when integer k is divided by 32..... i) 2 ii) 4 iii) 6 .... How to properly approach this ques?
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Rahul_Sharma23 wrote:
Q: When integer k^4 is divided by 32 the remainder is zero. Which of the following could be remainder when integer k is divided by 32..... i) 2 ii) 4 iii) 6 .... How to properly approach this ques?

­This question is discussed in detail here:

https://gmatclub.com/forum/when-k-4-is- ... 45729.html

Hope this helps.
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is anyone else facing this issue?

111.7.png

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Are you trying to take a test or practice questions?
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trying to access FE starter kit to take test
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Ah try the direct link. I need my computer to find it . 😔
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from here it is directly redirecting to the above URL.

111.8.png

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please share the link. @bb
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thank you!
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does that work better?
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yes
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👍👍 good luck!
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Thanks!
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Permutation and combination question :

a 10 digit number, which can include any number from 0 to 9. the first digit shall only be 6,7,8,9 and in the whole 10 digit number no digit should be repeated more than 4 times. like it’s upto 4 repetitions of any number are allowed. how many such possible 10 digit numbers exist?
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Options?
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4*10*10*10*9*9*9*9*8*8 ??
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sigmabale wrote:
Permutation and combination question : a 10 digit number, which can include any number from 0 to 9. the first digit shall only be 6,7,8,9 and in the whole 10 digit number no digit should be repeated more than 4 times. like it’s upto 4 repetitions of any number are allowed. how many such possible 10 digit numbers exist?

This looks like a nasty casework :(
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What’s the answer?
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Data Sufficiency Butler: April 2024
April 18DS 1DS 2
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Problem Solving Butler: April 2023
April 18PS 1PS 2
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HarshR9 wrote:
Hmm. We all got different answers. Hope Rahul shares the official answer soon! :)

Zero
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