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camping trip [#permalink]  20 Mar 2011, 20:13
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Question Stats:

13% (00:00) correct 87% (01:31) wrong based on 16 sessions
If 20 percent of the students at a certain school went to a camping trip and took more than \$100, and 75 percent of the students who went to the camping trip did not take more than \$100, what percentage of the students at the school went to the camping trip?

(A) 95
(B) 90
(C) 85
(D) 80
(E) 75
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Re: camping trip [#permalink]  20 Mar 2011, 22:54
Let x be the number of students in the school. 0.2x students went to the trip and took more than 100\$. They compose (100-75)=25% of all students who went to the trip. Therefore the toal of 0.2x/0.25=0.8x students went to the camping which is 80%.

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Re: camping trip [#permalink]  20 Mar 2011, 23:09
X -> Total # of students

Y -> went to camp

0.2x -> Camp with > \$100

0.75 * y -> Camp with < 100

So 0.25 of y took > \$100

0.25y = 0.2x

=> y/x = 20/25 * 100 = 80%

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Re: camping trip [#permalink]  07 Jun 2011, 07:26
what is the source of this question?
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Re: camping trip [#permalink]  07 Jun 2011, 07:37
dreambeliever wrote:
If 20 percent of the students at a certain school went to a camping trip and took more than \$100, and 75 percent of the students who went to the camping trip did not take more than \$100, what percentage of the students at the school went to the camping trip?

(A) 95
(B) 90
(C) 85
(D) 80
(E) 75

Better way to approach these kind of problems are pick a simple number (total) say we have a total 100 students. Now read the bolded part carefully- it prompts you immediately that (X-0.75X)= 0.25X (where x is the % students going for the camping) is the % total students (which is same as 20% of total students).

So 0.25X = 20% of 100 -> X= 80 so D
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Re: camping trip [#permalink]  11 Jun 2011, 07:09
Agree with D, good explanation bagrettin
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Re: camping trip [#permalink]  14 Jun 2011, 08:16
Can someone help me understand the question?
I must be sounding silly however my doubt is,
If 20% of students at a certain school went to a camping trip, then what is the point in asking the percentage of students at school who went to the camping trip?
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Re: camping trip [#permalink]  14 Jun 2011, 10:15
1
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shm0401 wrote:
Can someone help me understand the question?
I must be sounding silly however my doubt is,
If 20% of students at a certain school went to a camping trip, then what is the point in asking the percentage of students at school who went to the camping trip?

Genuine doubt:

[highlight]If 20 percent of the students at a certain school went to a camping trip AND took more than \$100[/highlight], and 75 percent of the students who went to the camping trip did not take more than \$100, what percentage of the students at the school went to the camping trip?

The highlighted part is one giant sentence and should be read together.

e.g.
100- Students
20- Students went to the trip AND also took more than \$100

Say, x students went to the trip.
So, x-20 will be the percent of student who took less than or equal to \$100 with them.

And it is given that this x-20=75% who went to the picnic
OR
x-20=0.75x
x=80
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Re: camping trip [#permalink]  14 Jun 2011, 18:22
Thank you Fluke.
The wordings in the problem are a problem themselves..
Re: camping trip   [#permalink] 14 Jun 2011, 18:22
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