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Senior Manager
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circle [#permalink] New post 06 Jul 2009, 02:24
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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
10. If A is the center of the circle shown above and AB=BC=CD, what is the value of x?

(A) 15
(B) 30
(C) 45
(D) 60
(E) 75
Figure attached...I am not sure of the answer. So wanted to check?
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Senior Manager
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Re: circle [#permalink] New post 06 Jul 2009, 02:25
Please explain your method as well.
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Re: circle [#permalink] New post 06 Jul 2009, 03:09
Ans is 30.
Right?
Plz confirm.
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Re: circle [#permalink] New post 06 Jul 2009, 03:19
Answer B.

Let BD intersects AC at X.
Triangles, BCX and ABX are congruent,
as, AB=BC.
angle AXB = angle BXC = 90 degree (as BC = CD)
and BX is common side for both triangles.

this implies, angle ABX = CBX ..... (i)

Triangle ABC is equilateral triangle (as AB=BC=AC)
This implies angle ABC = 60 degree .... (ii)

From (i) and (ii), we can say that angle ABX = CBX = 30
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Re: circle   [#permalink] 06 Jul 2009, 03:19
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