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# circle

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Senior Manager
Joined: 26 May 2009
Posts: 317
Followers: 2

Kudos [?]: 38 [0], given: 13

circle [#permalink]  06 Jul 2009, 01:24
00:00

Difficulty:

(N/A)

Question Stats:

100% (01:16) correct 0% (00:00) wrong based on 0 sessions
10. If A is the center of the circle shown above and AB=BC=CD, what is the value of x?

(A) 15
(B) 30
(C) 45
(D) 60
(E) 75
Figure attached...I am not sure of the answer. So wanted to check?
Attachments

circle.gif [ 3.99 KiB | Viewed 1056 times ]

Senior Manager
Joined: 26 May 2009
Posts: 317
Followers: 2

Kudos [?]: 38 [0], given: 13

Re: circle [#permalink]  06 Jul 2009, 01:25
Intern
Joined: 03 Jul 2009
Posts: 7
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: circle [#permalink]  06 Jul 2009, 02:09
Ans is 30.
Right?
Plz confirm.
Director
Joined: 03 Jun 2009
Posts: 803
Location: New Delhi
WE 1: 5.5 yrs in IT
Followers: 68

Kudos [?]: 467 [0], given: 56

Re: circle [#permalink]  06 Jul 2009, 02:19

Let BD intersects AC at X.
Triangles, BCX and ABX are congruent,
as, AB=BC.
angle AXB = angle BXC = 90 degree (as BC = CD)
and BX is common side for both triangles.

this implies, angle ABX = CBX ..... (i)

Triangle ABC is equilateral triangle (as AB=BC=AC)
This implies angle ABC = 60 degree .... (ii)

From (i) and (ii), we can say that angle ABX = CBX = 30
_________________
Re: circle   [#permalink] 06 Jul 2009, 02:19
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