Answer B.

Let BD intersects AC at X.

Triangles, BCX and ABX are congruent,

as, AB=BC.

angle AXB = angle BXC = 90 degree (as BC = CD)

and BX is common side for both triangles.

this implies, angle ABX = CBX ..... (i)

Triangle ABC is equilateral triangle (as AB=BC=AC)

This implies angle ABC = 60 degree .... (ii)

From (i) and (ii), we can say that angle ABX = CBX = 30

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