DS:Triangle : DS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 22 Jan 2017, 21:37

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# DS:Triangle

Author Message
Senior Manager
Joined: 02 Feb 2004
Posts: 345
Followers: 1

Kudos [?]: 62 [0], given: 0

### Show Tags

23 Mar 2005, 20:23
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

easy one;)
Attachments

0015.jpg [ 9.38 KiB | Viewed 1002 times ]

VP
Joined: 25 Nov 2004
Posts: 1493
Followers: 7

Kudos [?]: 98 [0], given: 0

### Show Tags

23 Mar 2005, 20:51
mirhaque wrote:
easy one

Cordinate of A is less than 3 so Agree with B.
but do not think it is easy.
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5062
Location: Singapore
Followers: 30

Kudos [?]: 358 [0], given: 0

### Show Tags

23 Mar 2005, 21:58
1) A < 3
So A can be 1 or 2 (assuing integers) Max area < 15.
Sufficient.

2)triangle is right
Not sufficient. Can't tell.

(A) - statement 1 is sufficient
VP
Joined: 18 Nov 2004
Posts: 1440
Followers: 2

Kudos [?]: 38 [0], given: 0

### Show Tags

24 Mar 2005, 13:44
"B".....

state 1....A can be -12 or 2....so different areas > or < 15...insuff

state 2.....there is only 2 points where the lines will be meet at right angle in Y axis(#2)...suff

Last edited by banerjeea_98 on 24 Mar 2005, 18:05, edited 1 time in total.
Director
Joined: 21 Sep 2004
Posts: 610
Followers: 1

Kudos [?]: 33 [0], given: 0

### Show Tags

24 Mar 2005, 17:46
banerjeea_98 wrote:
"B".....

state 1....A can be -12 or 2....so different areas > or < 15...insuff

state 2.....there is only 1 point where the lines will be meet at right angle in Y axis...suff

can u explain the statement 2? i am not too sure.. what u r talking about.
Attachments

triangle.GIF [ 2.16 KiB | Viewed 980 times ]

VP
Joined: 25 Nov 2004
Posts: 1493
Followers: 7

Kudos [?]: 98 [0], given: 0

### Show Tags

24 Mar 2005, 18:56
vprabhala wrote:
i thought it should be E..

if the triangle is a right triangle, the hypoteneous is 5 and other two sides (suppose one is height and other is base) have a maximum measurement of Sqrt(5/2). if so, then the maximum area of the triangle could be 1/2[sqrt(5/2)xsqrt(5/2)], which equal 12.5. this is the maximum possible are of the triangle with the given information. therefore, B is suff.

In the meantime, coordinates of A could be negative, not only positive.
Director
Joined: 27 Dec 2004
Posts: 905
Followers: 1

Kudos [?]: 43 [0], given: 0

### Show Tags

24 Mar 2005, 19:07
I pick (E)
There is nothing that tells us that the hypotenuse is 5 so why would we assume the longest side of the right triangle is the given side?
VP
Joined: 25 Nov 2004
Posts: 1493
Followers: 7

Kudos [?]: 98 [0], given: 0

### Show Tags

24 Mar 2005, 19:14
Folaa3 wrote:
I pick (E). There is nothing that tells us that the hypotenuse is 5 so why would we assume the longest side of the right triangle is the given side?

Folaa3, Note that third vertex of the triangle have coordinates (x, y) as (0, A). value of x = 0 means the value of lies somewhere on the verticle line and B says the triangle is right angle triangle. if you construct the right angle triangle with these constrains, you will find the hypoteneous, base and height, then the area, which is not more than 12.5, of the triangle.
Director
Joined: 27 Dec 2004
Posts: 905
Followers: 1

Kudos [?]: 43 [0], given: 0

### Show Tags

24 Mar 2005, 19:23
MA wrote:
Folaa3 wrote:
I pick (E). There is nothing that tells us that the hypotenuse is 5 so why would we assume the longest side of the right triangle is the given side?

Folaa3, Note that third vertex of the triangle have coordinates (x, y) as (0, A). value of x = 0 means the value of lies somewhere on the verticle line and B says the triangle is right angle triangle. if you construct the right angle triangle with these constrains, you will find the hypoteneous, base and height, then the area, which is not more than 12.5, of the triangle.

I don't get it MA.. if the value or x in the third vertex = 0, A (which is y) could be anywhere along the y-axis......ah shoooot! I got it...so no matter where A lies on the y-axis, both sides will be equal so it only makes sense that 5 be the hypotenus since a right angle triangle can only have 1 hypotheneous...Got it. Thanks MA
VP
Joined: 18 Nov 2004
Posts: 1440
Followers: 2

Kudos [?]: 38 [0], given: 0

### Show Tags

24 Mar 2005, 20:13
vp, in ur dia....if u see where the A,0 meets with either side of the axis u wud see that these 2 lines can meet in only 2 points on the yaxis and also be perpendicular ro each other, points r (0,2) and (0,-2)....A can be only these coordinates, so once we know A we know the area, whatever that may be.....If u r interested in calculating the A coordinate, try to think in terms of 2 lines meeting at (0,A) at penpendicular...u will see it can be #2
Director
Joined: 07 Jun 2004
Posts: 612
Location: PA
Followers: 5

Kudos [?]: 708 [0], given: 22

### Show Tags

25 Mar 2005, 02:47
its E A could be -18 or 1 or anything less than 3
Senior Manager
Joined: 02 Feb 2004
Posts: 345
Followers: 1

Kudos [?]: 62 [0], given: 0

### Show Tags

25 Mar 2005, 05:00
banerjeea_98 wrote:
"B".....

state 1....A can be -12 or 2....so different areas > or < 15...insuff

state 2.....there is only 2 points where the lines will be meet at right angle in Y axis(#2)...suff

Right on the mark. You made it simple but not any simpler
25 Mar 2005, 05:00
Display posts from previous: Sort by

# DS:Triangle

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.