let L and l be the corresponding heights in 2 traingles.

Let x and y be the corresponding legths of side in 2 triangles.

since the area of one is double.

1/2 SL = 2 * 1/2 sl

so, S=2sl/L.........eq 1

from similar triangle,

s/S= y/x

also y/x = l/L

hence l/L = s/S

putting this in eq 1

S=2*s*s/S

hence S = s*sqrt2

LM wrote:

I can't draw the figure here. ( nevertheless figures are not drawn to scale is given )

There are two triangles shown in a figure. Their corresponding angles are all equal. Lengths of sides are different. One has the base given as s and other one has the base S. Area of the triangle with base S is twice the area of triangle with base s. Then in terms os s, S=

the answer is (root2*s)

why?