let L and l be the corresponding heights in 2 traingles.
Let x and y be the corresponding legths of side in 2 triangles.
since the area of one is double.
1/2 SL = 2 * 1/2 sl
so, S=2sl/L.........eq 1
from similar triangle,
also y/x = l/L
hence l/L = s/S
putting this in eq 1
hence S = s*sqrt2
I can't draw the figure here. ( nevertheless figures are not drawn to scale is given )
There are two triangles shown in a figure. Their corresponding angles are all equal. Lengths of sides are different. One has the base given as s and other one has the base S. Area of the triangle with base S is twice the area of triangle with base s. Then in terms os s, S=
the answer is (root2*s)