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10 Dec 2006, 01:19
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I can't draw the figure here. ( nevertheless figures are not drawn to scale is given )
There are two triangles shown in a figure. Their corresponding angles are all equal. Lengths of sides are different. One has the base given as s and other one has the base S. Area of the triangle with base S is twice the area of triangle with base s. Then in terms os s, S=
the answer is (root2*s)
why?
There are two triangles shown in a figure. Their corresponding angles are all equal. Lengths of sides are different. One has the base given as s and other one has the base S. Area of the triangle with base S is twice the area of triangle with base s. Then in terms os s, S=
the answer is (root2*s)
why?
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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10 Dec 2006, 01:38
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let L and l be the corresponding heights in 2 traingles.
Let x and y be the corresponding legths of side in 2 triangles.
since the area of one is double.
1/2 SL = 2 * 1/2 sl
so, S=2sl/L.........eq 1
from similar triangle,
s/S= y/x
also y/x = l/L
hence l/L = s/S
putting this in eq 1
S=2*s*s/S
hence S = s*sqrt2
Let x and y be the corresponding legths of side in 2 triangles.
since the area of one is double.
1/2 SL = 2 * 1/2 sl
so, S=2sl/L.........eq 1
from similar triangle,
s/S= y/x
also y/x = l/L
hence l/L = s/S
putting this in eq 1
S=2*s*s/S
hence S = s*sqrt2
LM
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
