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Is x > y? (1) x^2 > y (2) x – |y| > 0

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Bunuel
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Is x > y? (1) x^2 > y (2) x – |y| > 0 [#permalink] New post   23 Mar 2016, 11:37
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77% (01:14) correct 23% (01:32) wrong based on 802 sessions
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Is x > y?

(1) x^2 > y

(2) x – |y| > 0
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B
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Bunuel
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0 [#permalink] New post   04 Dec 2017, 00:59
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Is x > y?

(1) x^2 > y:

If x = 1 and y = 0, then the answer will be YES.
If x = -1 and y = 0, then the answer will be NO.
Not sufficient.

(2) x – |y| > 0:

x > |y|. Now, if x is greater than the absolute value of y, then it must be greater than y itself. Sufficient.

Answer: B.
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0 [#permalink] New post   23 Mar 2016, 12:32
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Bunuel wrote:
Is x > y?

(1) x^2 > y

(2) x – |y| > 0


(1) x^2 > y

Let x^2=4 and y=3
then( x=2)<(y=3)......NO
but x^2=16 and y=3
then( x=4)>(y=3)......YES.
Insuff.....

(2) x – |y| > 0
x>IyI
it means x is a positive number
so x is always greater than Y wheather y is +ve or -ve
Suff...

Ans B
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0 [#permalink] New post   23 Mar 2016, 19:07
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Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

Is x > y?

(1) x^2 > y
(2) x – |y| > 0


In the question above, in 2), x>|y| becomes -x<y<x, which is yes and sufficient.
Thus, B is the answer.
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0 [#permalink] New post   27 Mar 2016, 21:28
Is x > y?

(1) x^2 > y
=> if y = 2 then for
x=3, x^2>y but x>y
x=-3, x^2>y but x<y
Insufficient.
(2) x – |y| > 0
x>lyl
lyl is always some positive value.
x is always positive with value greater then y.
Sufficient
B
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0 [#permalink] New post   09 Mar 2018, 00:32
Bunuel wrote:
Is x > y?

(1) x^2 > y

(2) x – |y| > 0


Question: Is x > y?

St 1: x^2 > y

Test some numbers: If x = 2 & y = 1,

then x^2 > y & also x > y

If x = -2 & y = 1,

then x^2 > y, but x < y

Insufficient

St 2: x – |y| > 0

means x > |y| (As we know absolute value is always >= 0)

If x > |y|, we can safely say that x > y

Sufficient.

(B)
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0 [#permalink] New post   26 Aug 2019, 06:57
Bunuel wrote:
Is x > y?

(1) x^2 > y

(2) x – |y| > 0


#1
x can b -ve or +ve insufficient
#2
x>lyl
y would be fraction value
IMO B
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0 [#permalink] New post   18 Nov 2019, 10:34
(1) x^2 > y .... can't able to prove anything

(2) x - |y| > 0
=> x-y > 0 => x>y
=> x+y > 0 => x > -y => -x<y
Thus -x<y<x. SUFFICIENT
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0 [#permalink] New post   20 Aug 2020, 08:11
Bunuel wrote:
Is x > y?

(1) x^2 > y

(2) x – |y| > 0


In (2), can we take lYl on the other side and square it?
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0 [#permalink] New post   02 Feb 2021, 12:41
Is x > y?

(1) x^2 > y
Clearly insufficient.
x can be positive or negative and x^2 can be greater than y.
x = -ve then y could be greater
x = +ve then y could be smaller

(2) x – |y| > 0
x > |y|
RHS is always positive so we know that x will always be greater than y
Sufficient.
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0 [#permalink] New post   04 Feb 2021, 03:00
VeritasKarishma plz explain
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0 [#permalink] New post   04 Feb 2021, 04:02
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Bunuel wrote:
Is x > y?

(1) x^2 > y

(2) x – |y| > 0



(1) x^2 > y

Say x = 2 so x^2 = 4.
We are given that 4 > y. Now note that y could be 3 or 1 (or infinite other values). So y may be greater than x or less than x.
Not sufficient


(2) x – |y| > 0

x > |y|

Note that |y| is always positive. So |y| is either equal to y (when y is positive) or |y| is greater than y (when y is negative).
So |y| >= y
Since x is greater than |y|, it is certainly greater than y too (since y is equal to |y| or less than |y|).
Sufficient

Answer (B)
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0 [#permalink] New post   13 Feb 2022, 10:30
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