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Bunuel
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Is x > y? (1) x^2 > y (2) x – |y| > 0 23 Mar 2016, 11:37
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B
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77% (01:14) correct 23% (01:32) wrong based on 808 sessions

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Is x > y?

(1) x^2 > y

(2) x – |y| > 0
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B
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Bunuel
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Is x > y? (1) x^2 > y (2) x – |y| > 0 04 Dec 2017, 00:59
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Is x > y?

(1) x^2 > y:

If x = 1 and y = 0, then the answer will be YES.
If x = -1 and y = 0, then the answer will be NO.
Not sufficient.

(2) x – |y| > 0:

x > |y|. Now, if x is greater than the absolute value of y, then it must be greater than y itself. Sufficient.

Answer: B.
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Is x > y? (1) x^2 > y (2) x – |y| > 0 23 Mar 2016, 12:32
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Bunuel
Is x > y?

(1) x^2 > y

(2) x – |y| > 0

(1) x^2 > y

Let x^2=4 and y=3
then( x=2)<(y=3)......NO
but x^2=16 and y=3
then( x=4)>(y=3)......YES.
Insuff.....

(2) x – |y| > 0
x>IyI
it means x is a positive number
so x is always greater than Y wheather y is +ve or -ve
Suff...

Ans B
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Is x > y? (1) x^2 > y (2) x – |y| > 0 23 Mar 2016, 19:07
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Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

Is x > y?

(1) x^2 > y
(2) x – |y| > 0


In the question above, in 2), x>|y| becomes -x<y<x, which is yes and sufficient.
Thus, B is the answer.
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Is x > y? (1) x^2 > y (2) x – |y| > 0 27 Mar 2016, 21:28
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Is x > y?

(1) x^2 > y
=> if y = 2 then for
x=3, x^2>y but x>y
x=-3, x^2>y but x<y
Insufficient.
(2) x – |y| > 0
x>lyl
lyl is always some positive value.
x is always positive with value greater then y.
Sufficient
B
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Is x > y? (1) x^2 > y (2) x – |y| > 0 09 Mar 2018, 00:32
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Bunuel
Is x > y?

(1) x^2 > y

(2) x – |y| > 0

Question: Is x > y?

St 1: x^2 > y

Test some numbers: If x = 2 & y = 1,

then x^2 > y & also x > y

If x = -2 & y = 1,

then x^2 > y, but x < y

Insufficient

St 2: x – |y| > 0

means x > |y| (As we know absolute value is always >= 0)

If x > |y|, we can safely say that x > y

Sufficient.

(B)
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Is x > y? (1) x^2 > y (2) x – |y| > 0 26 Aug 2019, 06:57
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Bunuel
Is x > y?

(1) x^2 > y

(2) x – |y| > 0

#1
x can b -ve or +ve insufficient
#2
x>lyl
y would be fraction value
IMO B
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Is x > y? (1) x^2 > y (2) x – |y| > 0 18 Nov 2019, 10:34
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(1) x^2 > y .... can't able to prove anything

(2) x - |y| > 0
=> x-y > 0 => x>y
=> x+y > 0 => x > -y => -x<y
Thus -x<y<x. SUFFICIENT
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Is x > y? (1) x^2 > y (2) x – |y| > 0 20 Aug 2020, 08:11
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Bunuel
Is x > y?

(1) x^2 > y

(2) x – |y| > 0

In (2), can we take lYl on the other side and square it?
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Is x > y? (1) x^2 > y (2) x – |y| > 0 02 Feb 2021, 12:41
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Is x > y?

(1) x^2 > y
Clearly insufficient.
x can be positive or negative and x^2 can be greater than y.
x = -ve then y could be greater
x = +ve then y could be smaller

(2) x – |y| > 0
x > |y|
RHS is always positive so we know that x will always be greater than y
Sufficient.
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Is x > y? (1) x^2 > y (2) x – |y| > 0 04 Feb 2021, 03:00
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VeritasKarishma plz explain
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Is x > y? (1) x^2 > y (2) x – |y| > 0 04 Feb 2021, 04:02
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Bunuel
Is x > y?

(1) x^2 > y

(2) x – |y| > 0


(1) x^2 > y

Say x = 2 so x^2 = 4.
We are given that 4 > y. Now note that y could be 3 or 1 (or infinite other values). So y may be greater than x or less than x.
Not sufficient


(2) x – |y| > 0

x > |y|

Note that |y| is always positive. So |y| is either equal to y (when y is positive) or |y| is greater than y (when y is negative).
So |y| >= y
Since x is greater than |y|, it is certainly greater than y too (since y is equal to |y| or less than |y|).
Sufficient

Answer (B)
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Is x > y? (1) x^2 > y (2) x – |y| > 0 13 Feb 2022, 10:30
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