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# Is x > y? (1) x^2 > y (2) x – |y| > 0

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Math Expert
Joined: 02 Sep 2009
Posts: 55228
Is x > y? (1) x^2 > y (2) x – |y| > 0  [#permalink]

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23 Mar 2016, 11:37
1
2
00:00

Difficulty:

25% (medium)

Question Stats:

77% (01:05) correct 23% (01:25) wrong based on 198 sessions

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Is x > y?

(1) x^2 > y

(2) x – |y| > 0

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Joined: 05 Mar 2015
Posts: 998
Re: Is x > y? (1) x^2 > y (2) x – |y| > 0  [#permalink]

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23 Mar 2016, 12:32
Bunuel wrote:
Is x > y?

(1) x^2 > y

(2) x – |y| > 0

(1) x^2 > y

Let x^2=4 and y=3
then( x=2)<(y=3)......NO
but x^2=16 and y=3
then( x=4)>(y=3)......YES.
Insuff.....

(2) x – |y| > 0
x>IyI
it means x is a positive number
so x is always greater than Y wheather y is +ve or -ve
Suff...

Ans B
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0  [#permalink]

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23 Mar 2016, 19:07
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

Is x > y?

(1) x^2 > y
(2) x – |y| > 0

In the question above, in 2), x>|y| becomes -x<y<x, which is yes and sufficient.
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0  [#permalink]

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27 Mar 2016, 21:28
Is x > y?

(1) x^2 > y
=> if y = 2 then for
x=3, x^2>y but x>y
x=-3, x^2>y but x<y
Insufficient.
(2) x – |y| > 0
x>lyl
lyl is always some positive value.
x is always positive with value greater then y.
Sufficient
B
Math Expert
Joined: 02 Sep 2009
Posts: 55228
Re: Is x > y? (1) x^2 > y (2) x – |y| > 0  [#permalink]

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04 Dec 2017, 00:59
Is x > y?

(1) x^2 > y:

If x = 1 and y = 0, then the answer will be YES.
If x = -1 and y = 0, then the answer will be NO.
Not sufficient.

(2) x – |y| > 0:

x > |y|. Now, if x is greater than the absolute value of y, then it must be greater than y itself. Sufficient.

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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0  [#permalink]

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09 Mar 2018, 00:32
Bunuel wrote:
Is x > y?

(1) x^2 > y

(2) x – |y| > 0

Question: Is x > y?

St 1: x^2 > y

Test some numbers: If x = 2 & y = 1,

then x^2 > y & also x > y

If x = -2 & y = 1,

then x^2 > y, but x < y

Insufficient

St 2: x – |y| > 0

means x > |y| (As we know absolute value is always >= 0)

If x > |y|, we can safely say that x > y

Sufficient.

(B)
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Re: Is x > y? (1) x^2 > y (2) x – |y| > 0   [#permalink] 09 Mar 2018, 00:32
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