udaymathapati wrote:

At what two points does the graph of y = (x+a)(x+b) intersect the x axis?

You don't need to worry what the equation represents. Just think, what does 'intersection with x axis' imply? It means the y co-ordinate is 0.

0 = (x+a)(x+b)

or x = -a or -b

Hence the graph must intersect the x axis at points (-a, 0) and (-b, 0). We need the values of a and b now.

Statement 1: a + b = -1

Two variables, only one equation. Not sufficient.

Statement 2: Graph intersects the y axis at (0, -6).

At y axis, x = 0. This means when x = 0, y co-ordinate is -6.

Put these values in y = (x+a)(x+b) to get -6 = ab.

Again, two variables, one equation. Not sufficient alone.

Using both statements, we have two variables and two different equations so we will be able to find the values of a and b. It doesn't matter which is 'a' and which is 'b'. We find that the two of them are -3 and 2. Since we need the points (-a, 0) and (-b, 0), the required points are (3, 0) and (-2, 0). Sufficient.

Answer (C).

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