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m03 #25

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Manager
Joined: 16 Sep 2010
Posts: 223
Location: United States
Concentration: Finance, Real Estate
GMAT 1: 740 Q48 V42
Followers: 8

Kudos [?]: 100 [0], given: 2

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14 Nov 2011, 23:00
C. Should that really be categorized under hardest problems? It tests your ability to pay attention to the prompt more than anything.
Manager
Joined: 21 Nov 2010
Posts: 133
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Kudos [?]: 5 [0], given: 12

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16 Nov 2011, 17:17
u0422811 wrote:
C. Should that really be categorized under hardest problems? It tests your ability to pay attention to the prompt more than anything.

I think it's the prompt and the putting A and B together, but I wouldn't rate this more than a 600-700 problem.
Intern
Joined: 22 May 2012
Posts: 14
GMAT 1: 660 Q49 V31
WE: Engineering (Computer Software)
Followers: 0

Kudos [?]: 0 [0], given: 7

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02 Oct 2012, 05:10
Another victim, chose E
Guess our brains are trained that way
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Joined: 20 Feb 2012
Posts: 47
WE: Consulting (Consulting)
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Kudos [?]: 3 [0], given: 11

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02 Oct 2012, 07:23
really somewhat tricky, but should not be among the hardest - just testing your attention to consider positive numbers only
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Joined: 15 May 2012
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Kudos [?]: 5 [0], given: 94

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15 Dec 2012, 19:24
I almost went for E because the second option gets to q=r and q=-r, but question stem says it is positive integers and hence ruled out q=-r.
Good one!
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Joined: 02 Sep 2009
Posts: 34453
Followers: 6275

Kudos [?]: 79614 [0], given: 10022

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01 Oct 2013, 05:17
Expert's post
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BELOW IS REVISED VERSION OF THIS QUESTION:

Are positive numbers $$p$$, $$q$$, and $$r$$ equal?

(1) $$p = q$$
(2) $$q^2 = r^2$$

(1) $$p = q$$. Not sufficient, since no info about $$r$$
(2) $$q^2 = r^2$$ --> since given that $$p$$ and $$q$$ are positive numbers then $$q=r$$. Not sufficient since no info about $$p$$.

(1)+(2) As $$p = q$$ and $$q=r$$ then $$p=q=r$$. Sufficient.

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Re: m03 #25   [#permalink] 01 Oct 2013, 05:17

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m03 #25

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