m03: Q30 : GMAT Club Tests

m03: Q30

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Intern

Joined: 24 Jun 2010

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Location: Toronto

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Re: m03: Q30 [#permalink]

28 Jul 2010, 13:01

Why do you need to take ratio of
Gold / Total
or
Silver / Total

Rather than using the ratio of gold/silver:
ie. (2x + 3y) / (3x + 7y) = 5/11
or someting like that?

Manager

Joined: 27 Jul 2010

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Location: Sweden

Concentration: Finance, International Business

Schools: Stockholm School of Economics (MSc Finance) - Class of 2014

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Re: m03: Q30 [#permalink]

20 Jul 2011, 03:33

amaterasu wrote:

Given Data:
Also my 2 cents:
1st bar= 2x gold, 3x silver total=5x
2nd bar= 3y gold, 7y silver total=10y

Melted into 8 kg= 2.5 gold, 5.5 silver according to the given ratio.

Entegration of the given data and solution:
So,
2x+3y=2.5
3x+7y=5.5
Solve for x, and 5x=1 is the answer

great explanation!

Manager

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Re: m03: Q30 [#permalink]

23 Jul 2011, 12:08

5g + 11s = 8
Therefore,
2.5 kgs of gold
5.5 kgs of silver
Solving for gold, there is 1 kg of gold in the first bar
Solving for silver, there is 1.65 kg of silver in the first bar
The total weight of the first bar is 2.65 kg.
_________________

petrifiedbutstanding

Senior Manager

Affiliations: UWC

Joined: 09 May 2012

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WE: Engineering (Entertainment and Sports)

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Re: m03: Q30 [#permalink]

02 Jun 2012, 00:55

This is how I did it but there seems to be a hole in my logic:

1st Bar: 2 : 3
2nd Bar: 3 : 7

Final Bar: 5 : 11 (given 8kg total)

So for the final bar, the multiplier x = 5x + 11x = 8 and x = 1/2.
So for the Final Bar the qty is 2.5 : 5.5

Now using this multiplier for the 1st and 2nd bar and comparing it to the 3rd bar:

1st Bar: 1 : 1.5
2nd Bar: 1.5 : 3.5

Thus 1 + 1.5 = 2.5 (OK) and

1.5 + 3.5 = 5 but, according to the original ratio this should be 5.5.

Where am I going wrong?

Intern

Joined: 02 Jul 2012

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Re: m03: Q30 [#permalink]

24 Jul 2012, 05:40

use allegation:

golda 2/5 goldb 3/10

5/16(mixture)

5/16-3/10=1/80 2/5-5/16=7/80

1:7mixture ratio
ie.===1kg out of 8 for GoldA

Re: m03: Q30 [#permalink] 24 Jul 2012, 05:40

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