M03Q20 : Retired Discussions [Locked] - Page 2
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# M03Q20

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Intern
Joined: 06 May 2009
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28 May 2013, 09:18
Dixon wrote:
Just curious, would something like this be a 600-level question?

It was correctly answered by 83% of the people, I would say in the 500-600 range.
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13 May 2014, 04:08
The answer is actually pretty easy. We are looking for an integer that divides 15! + 13, so (15! + 13) / q = n for some integers q and n. Using properties of fractions, this means (15!/q)+ (13/q) = n. Since 13 is prime, we know q must be 1 or 13. 1 is not an answer choice, so q must be 13. This can be checked further because by noting that 15!=15x14x13x12..., so we see 13 divides 15!, because 13 divides the third term of the factorial. Therefore 13 divides 15! and13, so 13 divides 15!+13 based on the above property of fractions.

The solution factoring out 13 is a better solution though.
Re: M03Q20   [#permalink] 13 May 2014, 04:08

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# M03Q20

Moderator: Bunuel

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