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m04 #04

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Re: m04 #04 [#permalink] New post 28 Mar 2011, 01:42
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rajeshaaidu wrote:
karthikp1211 wrote:
@rajeshaaidu : We are talking about the Total number of male students and female students in seperate here.With refence to the post above,the second case assumes the values M = 1 and F = 2.So the Total number of female students are 200 and the male students will still be 100.
So the Males in MIS will be 12 percent of 100 as explained.


How we could take seperatly? It's given total number of student enrolled in the MIS and not the total number of female or male student enrolled in the college. so the assumption taken by getting the answer as E is doubtful.


Let me explain you...

Suppose you consider the total number of students as 100. Statement 1 does not mean that 5% (i.e 5) of them are males. It says 5% of the total male students and not the Total students, which is the reason why the seperate totals are considered here...Hope this clears the air...
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Re: m04 #04 [#permalink] New post 28 Mar 2011, 01:56
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@kartik:
thnx for correcting me... :(
it wont get cancelled and thats y d ans shud be e.

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Re: m04 #04 [#permalink] New post 28 Mar 2011, 09:46
yes it is E....confusing one...
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Re: m04 #04 [#permalink] New post 28 Mar 2011, 20:31
karthikp1211 wrote:
rajeshaaidu wrote:
karthikp1211 wrote:
@rajeshaaidu : We are talking about the Total number of male students and female students in seperate here.With refence to the post above,the second case assumes the values M = 1 and F = 2.So the Total number of female students are 200 and the male students will still be 100.
So the Males in MIS will be 12 percent of 100 as explained.


How we could take seperatly? It's given total number of student enrolled in the MIS and not the total number of female or male student enrolled in the college. so the assumption taken by getting the answer as E is doubtful.


Let me explain you...

Suppose you consider the total number of students as 100. Statement 1 does not mean that 5% (i.e 5) of them are males. It says 5% of the total male students and not the Total students, which is the reason why the seperate totals are considered here...Hope this clears the air...



I think you are right! Thanks for your explanation and patience. +1 for you.
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Re: m04 #04 [#permalink] New post 31 Aug 2011, 07:48
Wow, this is an awesome question. Some described this question as poorly worded but is not. The wording is right. It is just you need to read the question carefully. Provided information does not mention total population whatsoever but it does mention that the 5% of total female population and 12% of the total male population at WU study MIS. Given these information one can never solve the problem.
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Re: m04 #04 [#permalink] New post 02 Apr 2012, 00:32
IMO E


we dont have required data to cal required answer
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Re: m04 #04 [#permalink] New post 01 Apr 2013, 02:56
Ans : e
Let there be 1000 students in Winconsin university of which M are male and W are female.
 M + W = 1000 - (i)
 Required:
% of female students among the total students enrolled in MIS (i.e.:
(Female enrolled in in MIS “a” ) / (Male enrolled in MIS “b” + Female enrolled in MIS “a”)

Case 1:
5% women in Wisconsin studying MIS (a) = 5% of W = .05W
We do not have value of “a” or “b”.
Not sufficient

Case 2:
12% of men in Wisconsin studying MIS (b) = 12% of M = .12M
We do not have value of “a” or “b”.
Not sufficient.

Case 3: Combining case 1 and case 2, we have value of men and women studying MIS when the total number of students is 1000.
Students studying MIS : .05W + .12 M
But we do not value of W and M.

Not sufficient

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Re: m04 #04 [#permalink] New post 01 Apr 2013, 04:34
E (Insufficient information)

Lets make a table

Female Male
MIS Course 5% of total female M=12% of total Male
Other Courses 95% 88%
Total in Wiscosin Univ = 200 100% 100%

For 1st statement, we can look at Female column, everything is in percentage.. we are not given a whole number a ratio with respect to Female studentsa ratio with respect to Female students such as total number of Female students or a ratio with respect to male students... Not sufficient

For 2nd statement, we can look at Male column, everything is in percentage.. we are not given a whole number such as total number of students and a ratio with respect to Female students... Not sufficient


Combining Both 1 & 2 statements, again we don't have a whole number such as total number of students or total number of girl students.
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Re: m04 #04 [#permalink] New post 01 Apr 2013, 08:00
It has to be answer c!

You are not understanding the question...

the question asks what percent of MIS students... so the total population should be MIS students at Winsconsin University...

Therefore, we know that 5/17 % of the MIS students at Winsconsin University are female.

Anwer is c!
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Re: m04 #04 [#permalink] New post 01 Apr 2013, 08:27
C should be the answer.
If 100 is total no. of Students in W Univesity,
a) then there are 5 nos. of students who are women and MIS student and
b) there are 12 nos. of Students who are men

So 5 / (5+17) is ratio of women to total students who are pursuing MIS in W University. Hence we need both the statements to answer the question.
The answer is C
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Re: m04 #04 [#permalink] New post 01 Apr 2013, 23:04
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amitbharadwaj7 wrote:
C should be the answer.
If 100 is total no. of Students in W Univesity,
a) then there are 5 nos. of students who are women and MIS student and
b) there are 12 nos. of Students who are men

So 5 / (5+17) is ratio of women to total students who are pursuing MIS in W University. Hence we need both the statements to answer the question.
The answer is C


I think your answer is not correct.

Statement 1 says: 5% of Female students study MIS, not 5% of TOTAL students are Female & study MIS. For instance, there are 100 students, 40 are female, and 5% of 40 is 2 students.

Statement 2: 12% of Male students study MIS, not 12% of TOTAL students are MALE & study MIS.

E is correct. The question is tricky because we only know 5% of F, and 12% of M, but we don't know the ratio between F and M.

For example:
1000 Students, 400F, 600M. So 5% of 400 = 20, 12% of 600 = 72 --> % F & MIS = 20/(20 + 72) = 21.7%
1000 students, 500F, 500M. So 5% of 500 = 25, 12% of 500 = 60 --> % F & MIS = 25/(25 + 60) = 29.4%

Hope it's clear.

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Re: m04 #04 [#permalink] New post 02 Apr 2013, 01:47
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What percent of the MIS students enrolled at Wisconsin University are female?

We want to calculate \frac{MIS_{female}}{MIS_{female}+MIS_{male}}

(1) 5% of female students at Wisconsin University are studying MIS. If there are total of X female students at Wisconsin University then 0.05X=MIS_{female}. Not sufficient.

(2) 12% of male students at Wisconsin University are studying MIS. If there are total of Y male students at Wisconsin University then 0.12Y=MIS_{male}. Not sufficient.

(1)+(2) \frac{MIS_{female}}{MIS_{female}+MIS_{male}}=\frac{0.05X}{0.05X+0.12Y}, still not sufficient to calculate the desired ratio.

Answer: E.

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Re: m04 #04 [#permalink] New post 04 Apr 2013, 07:20
You need to know the total number of students enrolled in the MIS program, which is not given... you're given the total of females at the university studying MIS, agree?

So neither pieces of information are sufficient to answer the question
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Re: m04 #04 [#permalink] New post 05 Apr 2013, 18:53
can anyone explain me i have doubt over here

the question asked was how students were enrolled and options 1) and 2) shows how many are studying doesn't they differ
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Re: m04 #04 [#permalink] New post 05 Apr 2013, 22:31
1. We don't know total number of students at WU and total number of MIS students. Not sufficient. Option A and D out.
2. We don't know total number of students at WU and total number of MIS students. Not sufficient. Option B out.

Together: We do not know the proportion of male and female students at WU. Not sufficient. Option C out.

Answer is E.
Re: m04 #04   [#permalink] 05 Apr 2013, 22:31
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