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M04-04

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M04-04 [#permalink]

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What percent of the MIS students enrolled at Wisconsin University are female?


(1) 5% of female students at Wisconsin University are studying MIS.

(2) 12% of male students at Wisconsin University are studying MIS.
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We want to calculate \(\frac{MIS_{\text{female}}}{MIS_{\text{female}}+MIS_{\text{male}}}\)

(1) 5% of female students at Wisconsin University are studying MIS. If there are total of \(X\) female students at Wisconsin University then \(0.05X=MIS_{\text{female}}\). Not sufficient.

(2) 12% of male students at Wisconsin University are studying MIS. If there are total of \(Y\) male students at Wisconsin University then \(0.12Y=MIS_{\text{male}}\). Not sufficient.

(1)+(2) \(\frac{MIS_{\text{female}}}{MIS_{\text{female}}+MIS_{\text{male}}}=\frac{0.05X}{0.05X+0.12Y}\), still not sufficient to calculate the desired ratio.


Answer: E
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New post 01 Mar 2016, 08:02
Hi Bunuel,

could I not just come up with a total number of stundents in order to calculate from S1 the number of female MIS stundents and from S2 the number of male stundents so that I can afterwards calculate the precent of female students in the MIS class?

Where am I going wrong? I somehow always ended up with ~29%.

Thanks for your help.

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M04-04 [#permalink]

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New post 01 Mar 2016, 08:10
Erina89 wrote:
Hi Bunuel,

could I not just come up with a total number of stundents in order to calculate from S1 the number of female MIS stundents and from S2 the number of male stundents so that I can afterwards calculate the precent of female students in the MIS class?

Where am I going wrong? I somehow always ended up with ~29%.

Thanks for your help.

Best


Let me try to answer. The issue with %ages in DS questions is that you will get different values for different total student number.

Case 1, lets say total students are = 100 ---> S1 gives females in MIS as 0.05*100 = 5

Case 2, lets say total students are = 200 ---> S1 gives females in MIS as 0.05*200 = 10

Thus, you get 2 different answers for the same question, what is %age (wrt total students) of females in MIS. This is the reason why S1 is not sufficient. Your approach would have worked for PS questions but for DS questions be wary of the percentages when the total number is not provided.

Hope this helps.

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Re: M04-04 [#permalink]

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New post 16 Sep 2016, 05:40
since its percent I took 100 for example
where am I going wrong?
>> !!!

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New post 06 Apr 2017, 22:17
Dear Bunnel,

Can you please help to explain the basic phrasing of this?
I got confused and choose D (Both are sufficient).

Statement 1: Only 5% are females are studying MIS at W University then, 5% is the answer I concluded.
Statement 2: Same as above for males, so we can conclude females % from there.

Help me to correct the understanding of this question.

Thanks
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New post 19 Sep 2017, 15:10
Hello,

Can we say that X+Y = 100% as all people are or male or female at MIS and so replace Y= 100-X in the equation you had with "both together"?

Kind regards,

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New post 19 Sep 2017, 21:52
Tpral wrote:
Hello,

Can we say that X+Y = 100% as all people are or male or female at MIS and so replace Y= 100-X in the equation you had with "both together"?

Kind regards,


x and y in the solution are the number of males and females, not percentage, so you cannot say that x + y = 100.
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Re M04-04 [#permalink]

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New post 23 Oct 2017, 19:29
I think this is a poor-quality question and the explanation isn't clear enough, please elaborate. Why if the question is asking for a percentage of students, which is given by both 1 & 2, unable to be attained? Can you not give the amount of students on a 100% basis and thus derive a % of female students? A formal number of students is not given but is not needed as a percentage is given and the percentage of students will not change given a change in student numbers. The word "percent" in the question stem needs to be clarified.

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New post 23 Nov 2017, 10:42
I think this is a poor-quality question and I don't agree with the explanation. Lets say "W" is the number of Wisconsin University students.

(1) MIS Females = 0.05W and (2) MIS Male = 0.12W

so (1) and (2) alone are not sufficient.

BUT, if we take both statement together we have :

%age of MIS Female = 0.05W / (0.05W+0.12W) = 0.05/0.17 ± 29.41%

So the W or the number of students at the university is not necessary to answer the question to me

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New post 23 Nov 2017, 10:57
itsFanny wrote:
I think this is a poor-quality question and I don't agree with the explanation. Lets say "W" is the number of Wisconsin University students.

(1) MIS Females = 0.05W and (2) MIS Male = 0.12W

so (1) and (2) alone are not sufficient.

BUT, if we take both statement together we have :

%age of MIS Female = 0.05W / (0.05W+0.12W) = 0.05/0.17 ± 29.41%

So the W or the number of students at the university is not necessary to answer the question to me


You are wrong.

From (1): 5% of female students at Wisconsin University are studying MIS.

0.05(female students at Wisconsin University) = (female students studying MIS)

From (2): 12% of male students at Wisconsin University are studying MIS.

0.12(male students at Wisconsin University) = (male students studying MIS)/

Please re-read the solution above carefully. This is clearly explained there.
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Re: M04-04   [#permalink] 23 Nov 2017, 10:57
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