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m04 #04 [#permalink] New post 18 Apr 2009, 00:19
What percent of the MIS students enrolled at Wisconsin University are female?

1. 5% of female students at Wisconsin University are studying MIS.
2. 12% of male students at Wisconsin University are studying MIS.

[Reveal] Spoiler: OA
E

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How is the solution (E)?Is'nt it (A) as the first statement is stating what exactly the ques is asking?what am i missing guys?

SOLUTION IS HERE: m04-77883-20.html#p1206767
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Re: m04 #04 [#permalink] New post 18 Apr 2009, 16:58
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suyashjhawar wrote:
What percent of the MIS students enrolled at Wisconsin University are female?

1. 5% of female students at Wisconsin University are studying MIS.
2. 12% of male students at Wisconsin University are studying MIS.

How is the solution (E)?Is'nt it (A) as the first statement is stating what exactly the ques is asking?what am i missing guys?


These very confusing question. Lets understand the question:
Question is: what is (Female student in MIS program / total students in MIS program) at Wisconsin University

1: 5% of female students at Wisconsin University are studying MIS
Total student at Wisconsin University = x = 2000
Female students at Wisconsin University studying MIS = 5% of 2,000 = 100

So what is the total number of MIS students at Wisconsin University? do not know...NSF.

2. 12% of male students at Wisconsin University are studying MIS
Total student at Wisconsin University = x = 2000
Male students at Wisconsin University are studying MIS = 12% of 2,000 = 240

So what is the total number of MIS students at Wisconsin University? do not know...NSF.

1&2: Also NSF as total number of MIS students at Wisconsin University.

So E.
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Re: m04 #04 [#permalink] New post 23 Apr 2009, 04:13
Hi guys,

I don't fully understand the reply.
The question stem asks for a percentage, so a ratio, right?
Then you COULD answer the question with S.1 AND S.2 together.

Let's take the explanation above:
IF the total number of uni students is 2000, you know 100 of them are female MIS and 240 are male MIS. Then the total is 340. So 100/340 * 100 = 29.41... %

Now you can say you DON'T know the number of students of the whole university, that's true but that doesn't matter cause let's say there are 1000 students then the numbers will be: 50 female MIS, 120 male MIS, so the ratio becomes 50/170. (This multiplying by 100 gives the same 29.41... percentage.

Finally the most simple way to dissolve this problem is you know the percentage of the MIS students. 5/12, then you know that the "total" makes 17 and then all you have to do is divide 5 by the "total" of 17.

So in my opinion the answer should be C.
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Re: m04 #04 [#permalink] New post 24 Apr 2009, 11:25
Should be C.
From 1 and 2 we can get the number of males+females studying MIS. Then we are done, we can get the percentage of MIS students who are females.

Any takers?
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Re: m04 #04 [#permalink] New post 26 Apr 2009, 20:55
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You need to know how many male and female are there in Wisconsin.

For example:
If Wisconsin had 1000 female, 5% of 1000 is 50
If Wisconsin only had 100 male, 12% of 100 is 12
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Re: m04 #04 [#permalink] New post 12 May 2009, 12:05
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this is a very badly worded question. whoever wrote this needs to get their head examined. i had the same issue that is being asked here. you would rarely see as badly worded a question like this on the GMAT. needless to say, this doesnt help students prepping. in fact, it only worsens things. horrible.
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Re: m04 #04 [#permalink] New post 14 May 2009, 18:25
suyashjhawar wrote:
What percent of the MIS students enrolled at Wisconsin University are female?

1.5% of female students at Wisconsin University are studying MIS.
2.12% of male students at Wisconsin University are studying MIS.

How is the solution (E)?Is'nt it (A) as the first statement is stating what exactly the ques is asking?what am i missing guys?


Similar to this question was discussed many times earlier. One of those discussion is here: settings-57078.html?highlight=motorists
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Re: m04 #04 [#permalink] New post 23 Mar 2010, 05:17
I agree with Sosso, should be C no ?
I also find 29.41..%

By the way this is my first post, happy to be here :-D
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Re: m04 #04 [#permalink] New post 23 Mar 2010, 06:17
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let F be number of female and M be number of male student at MIS enrolled at Wisconsin University

then we need to determine F/(F+M) with given statmetns
1) it says if TF is total female student at Wisconsin University
=> F = 0.05TF
with this we cant determine value of F/(F+M)

2) it says if TM is total male student at Wisconsin University
=> M = 0.12TM
again with this we cant determine value of F/(F+M)

now combining both:
F/(F+M) = 0.5TF/(0.05TF+0.12TM)
=> we cant determine value of F/(F+M)
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Re: m04 #04 [#permalink] New post 23 Mar 2010, 07:04
ok thanks sandeep, got it
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Re: m04 #04 [#permalink] New post 23 Mar 2010, 10:47
then we need to determine F/(F+M) with given statmetns
1) it says if TF is total female student at Wisconsin University
=> F = 0.05TF
with this we cant determine value of F/(F+M)

2) it says if TM is total male student at Wisconsin University
=> M = 0.12TM
again with this we cant determine value of F/(F+M)

now combining both:
F/(F+M) = 0.5TF/(0.05TF+0.12TM)
=> we cant determine value of F/(F+M)

copying sandeep

You can't know the actual number of females, BUT, you can know the % which is what the question is asking.
TF, stands for 100% of the females, and TM stands for 100% of the males, so with this, you can get the % of females in wisconsin enrolled in MIS

F/(F+M) = 0.05(1)/(0.05(1)+0.12(1))
F/(F+M) = 0.05/0.17
F/(F+M) = 29.41%

answer C.
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Re: m04 #04 [#permalink] New post 24 Mar 2010, 02:45
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It has to be E.


Let 100F = total females in Wisconsin University
Let 100M = total males in Wisconsin University

stmt1:
=> 5F are in MIS Dept.
No info about men, so INSUFF

stmt2:
=> 12M are in MIS Dept
No info about females, so, INSUFF

Combining 1&2:
females in MIS = 5F
Males in MIS = 12M
females/total students = 5F/(12M+5F)
we don't know the relative values of F and M. So, INSUFF.

Examples:
case 1:
Let F = M = 1;
i.e Females in MIS = 5
Males in MIS = 12
ratio = 5/(12+5) = 29%

case 2:
Let F = 2; and M = 1.
females in MIS = 10; males in MIS = 12
ratio = 10/(12+10) = 10/22
= 45%

29 IS NOT EQUAL TO 45%.
Therefore, the correct response should be E.
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Re: m04 #04 [#permalink] New post 09 Sep 2010, 01:49
chouky wrote:
I agree with Sosso, should be C no ?
I also find 29.41..%

By the way this is my first post, happy to be here :-D

me too
I agree with Sosso
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Re: m04 #04 [#permalink] New post 11 Sep 2010, 20:13
Answer is E..

In both the statements we are unable to find the % of female students in the university and the requirement is to find the % of total students who are females in the university who study MIS.
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Re: m04 #04 [#permalink] New post 26 Mar 2011, 05:04
Let there be M males and W females in Wisconsin University

So we're asked -> Females MIS/(Female MIS + Male MIS)/ = ?

So From (1)

0.5F -> MIS Female, not sufficient

and from (2)

0.12M -> MIS Male, not sufficient

From (1) and (2) -> 0.5F/(0.5F + 0.12M) = ?

which can't be calculated from the given information.

Answer - E
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Re: m04 #04 [#permalink] New post 26 Mar 2011, 05:26
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:-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D
a poor worded question.
consider the total no of students be 100
if x be the no of males and 100-x be the no of females.
Statement 1 says that 5% of the female students at wisconsin university are studying MIS. then 0.05(100-x) is the no of females studying MIS. but its not possible to find out the percentage of the female students studying MIS. hence data insufficient

Statement 2 says that 12% of the male students of the univ. are studying MIS. then it means that .12x of the males are studying MIS.. still data is insufficient to find pout the percentage of the female students studying MIS

on combining the two statements,
we get the total no of female students studying MIS as well as the total no of male students studying MIS.
therefore percentage of the female students in the mis class is:-
[0.05(100-x)]/[0.05(100-x)+0.12x]
while solving, x will be cancelled and the percentage can be obtained.

final answerc

still i am nt happy by this type of questions coz they are poorly worded and rather preparing students for prep for GMAT they are pegging up the students.
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Re: m04 #04 [#permalink] New post 27 Mar 2011, 20:47
gmatbull wrote:
It has to be E.


Let 100F = total females in Wisconsin University
Let 100M = total males in Wisconsin University

stmt1:
=> 5F are in MIS Dept.
No info about men, so INSUFF

stmt2:
=> 12M are in MIS Dept
No info about females, so, INSUFF

Combining 1&2:
females in MIS = 5F
Males in MIS = 12M
females/total students = 5F/(12M+5F)
we don't know the relative values of F and M. So, INSUFF.

Examples:
case 1:
Let F = M = 1;
i.e Females in MIS = 5
Males in MIS = 12
ratio = 5/(12+5) = 29%

case 2:
Let F = 2; and M = 1.
females in MIS = 10; males in MIS = 12; Put 12% i.e 24 and check
ratio = 10/(12+10) = 10/22
= 45%

29 IS NOT EQUAL TO 45%.
Therefore, the correct response should be E.


I don't agree with you. In the second case how you can take males in MIS=12? In the first case you have taken total number of student to be 100 then number of female=5 and male=12. Similarly, if you double the number of student to be 200 then number of female student should be 10 and male=24 and not 12, because you have to calculate 12% of total number. This will again give 29%. So, the answer should be C. Can you explain where I am going wrong?
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Re: m04 #04 [#permalink] New post 27 Mar 2011, 22:37
@rajeshaaidu : We are talking about the Total number of male students and female students in seperate here.With refence to the post above,the second case assumes the values M = 1 and F = 2.So the Total number of female students are 200 and the male students will still be 100.
So the Males in MIS will be 12 percent of 100 as explained.
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Re: m04 #04 [#permalink] New post 27 Mar 2011, 22:47
siddharthasingh wrote:
:-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D
a poor worded question.
consider the total no of students be 100
if x be the no of males and 100-x be the no of females.
Statement 1 says that 5% of the female students at wisconsin university are studying MIS. then 0.05(100-x) is the no of females studying MIS. but its not possible to find out the percentage of the female students studying MIS. hence data insufficient

Statement 2 says that 12% of the male students of the univ. are studying MIS. then it means that .12x of the males are studying MIS.. still data is insufficient to find pout the percentage of the female students studying MIS

on combining the two statements,
we get the total no of female students studying MIS as well as the total no of male students studying MIS.
therefore percentage of the female students in the mis class is:-
[0.05(100-x)]/[0.05(100-x)+0.12x]
while solving, x will be cancelled and the percentage can be obtained.

final answerc

still i am nt happy by this type of questions coz they are poorly worded and rather preparing students for prep for GMAT they are pegging up the students.


How will X be cancelled in the Expression above mate..:) ??

Answer should be (E)
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Re: m04 #04 [#permalink] New post 28 Mar 2011, 01:30
karthikp1211 wrote:
@rajeshaaidu : We are talking about the Total number of male students and female students in seperate here.With refence to the post above,the second case assumes the values M = 1 and F = 2.So the Total number of female students are 200 and the male students will still be 100.
So the Males in MIS will be 12 percent of 100 as explained.


How we could take seperatly? It's given total number of student enrolled in the MIS and not the total number of female or male student enrolled in the college. so the assumption taken by getting the answer as E is doubtful.
Re: m04 #04   [#permalink] 28 Mar 2011, 01:30
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