Find all School-related info fast with the new School-Specific MBA Forum

It is currently 25 Jul 2014, 03:48

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

m04 #04

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Director
Director
avatar
Joined: 18 Feb 2008
Posts: 509
Location: Kolkata
Followers: 5

Kudos [?]: 58 [0], given: 66

GMAT Tests User
m04 #04 [#permalink] New post 18 Apr 2009, 00:19
What percent of the MIS students enrolled at Wisconsin University are female?

1. 5% of female students at Wisconsin University are studying MIS.
2. 12% of male students at Wisconsin University are studying MIS.

[Reveal] Spoiler: OA
E

Source: GMAT Club Tests - hardest GMAT questions

How is the solution (E)?Is'nt it (A) as the first statement is stating what exactly the ques is asking?what am i missing guys?

SOLUTION IS HERE: m04-77883-20.html#p1206767
Kaplan Promo CodeKnewton GMAT Discount CodesGMAT Pill GMAT Discount Codes
3 KUDOS received
Manager
Manager
avatar
Joined: 13 Dec 2009
Posts: 131
Followers: 5

Kudos [?]: 192 [3] , given: 10

GMAT Tests User
Re: m04 #04 [#permalink] New post 23 Mar 2010, 06:17
3
This post received
KUDOS
let F be number of female and M be number of male student at MIS enrolled at Wisconsin University

then we need to determine F/(F+M) with given statmetns
1) it says if TF is total female student at Wisconsin University
=> F = 0.05TF
with this we cant determine value of F/(F+M)

2) it says if TM is total male student at Wisconsin University
=> M = 0.12TM
again with this we cant determine value of F/(F+M)

now combining both:
F/(F+M) = 0.5TF/(0.05TF+0.12TM)
=> we cant determine value of F/(F+M)
2 KUDOS received
Intern
Intern
avatar
Joined: 17 Mar 2008
Posts: 12
Followers: 0

Kudos [?]: 4 [2] , given: 5

Re: m04 #04 [#permalink] New post 12 May 2009, 12:05
2
This post received
KUDOS
this is a very badly worded question. whoever wrote this needs to get their head examined. i had the same issue that is being asked here. you would rarely see as badly worded a question like this on the GMAT. needless to say, this doesnt help students prepping. in fact, it only worsens things. horrible.
2 KUDOS received
Director
Director
avatar
Joined: 21 Dec 2009
Posts: 588
Concentration: Entrepreneurship, Finance
Followers: 15

Kudos [?]: 233 [2] , given: 20

GMAT Tests User
Re: m04 #04 [#permalink] New post 24 Mar 2010, 02:45
2
This post received
KUDOS
It has to be E.


Let 100F = total females in Wisconsin University
Let 100M = total males in Wisconsin University

stmt1:
=> 5F are in MIS Dept.
No info about men, so INSUFF

stmt2:
=> 12M are in MIS Dept
No info about females, so, INSUFF

Combining 1&2:
females in MIS = 5F
Males in MIS = 12M
females/total students = 5F/(12M+5F)
we don't know the relative values of F and M. So, INSUFF.

Examples:
case 1:
Let F = M = 1;
i.e Females in MIS = 5
Males in MIS = 12
ratio = 5/(12+5) = 29%

case 2:
Let F = 2; and M = 1.
females in MIS = 10; males in MIS = 12
ratio = 10/(12+10) = 10/22
= 45%

29 IS NOT EQUAL TO 45%.
Therefore, the correct response should be E.
_________________

KUDOS me if you feel my contribution has helped you.

1 KUDOS received
CEO
CEO
User avatar
Joined: 29 Aug 2007
Posts: 2501
Followers: 51

Kudos [?]: 484 [1] , given: 19

GMAT Tests User
Re: m04 #04 [#permalink] New post 18 Apr 2009, 16:58
1
This post received
KUDOS
suyashjhawar wrote:
What percent of the MIS students enrolled at Wisconsin University are female?

1. 5% of female students at Wisconsin University are studying MIS.
2. 12% of male students at Wisconsin University are studying MIS.

How is the solution (E)?Is'nt it (A) as the first statement is stating what exactly the ques is asking?what am i missing guys?


These very confusing question. Lets understand the question:
Question is: what is (Female student in MIS program / total students in MIS program) at Wisconsin University

1: 5% of female students at Wisconsin University are studying MIS
Total student at Wisconsin University = x = 2000
Female students at Wisconsin University studying MIS = 5% of 2,000 = 100

So what is the total number of MIS students at Wisconsin University? do not know...NSF.

2. 12% of male students at Wisconsin University are studying MIS
Total student at Wisconsin University = x = 2000
Male students at Wisconsin University are studying MIS = 12% of 2,000 = 240

So what is the total number of MIS students at Wisconsin University? do not know...NSF.

1&2: Also NSF as total number of MIS students at Wisconsin University.

So E.
_________________

Verbal: new-to-the-verbal-forum-please-read-this-first-77546.html
Math: new-to-the-math-forum-please-read-this-first-77764.html
Gmat: everything-you-need-to-prepare-for-the-gmat-revised-77983.html


GT

Expert Post
1 KUDOS received
VP
VP
avatar
Joined: 07 Apr 2009
Posts: 1114
Concentration: General Management, Strategy
Schools: Duke (Fuqua) - Class of 2012
Followers: 26

Kudos [?]: 320 [1] , given: 19

GMAT Tests User Premium Member
Re: m04 #04 [#permalink] New post 26 Apr 2009, 20:55
1
This post received
KUDOS
Expert's post
You need to know how many male and female are there in Wisconsin.

For example:
If Wisconsin had 1000 female, 5% of 1000 is 50
If Wisconsin only had 100 male, 12% of 100 is 12
_________________

Diversity

Expert Post
1 KUDOS received
Verbal Forum Moderator
Verbal Forum Moderator
User avatar
Status: Preparing for the another shot...!
Joined: 03 Feb 2011
Posts: 1425
Location: India
Concentration: Finance, Marketing
GPA: 3.75
Followers: 123

Kudos [?]: 569 [1] , given: 62

GMAT ToolKit User GMAT Tests User Premium Member
Re: m04 #04 [#permalink] New post 26 Mar 2011, 05:26
1
This post received
KUDOS
Expert's post
:-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D :-D
a poor worded question.
consider the total no of students be 100
if x be the no of males and 100-x be the no of females.
Statement 1 says that 5% of the female students at wisconsin university are studying MIS. then 0.05(100-x) is the no of females studying MIS. but its not possible to find out the percentage of the female students studying MIS. hence data insufficient

Statement 2 says that 12% of the male students of the univ. are studying MIS. then it means that .12x of the males are studying MIS.. still data is insufficient to find pout the percentage of the female students studying MIS

on combining the two statements,
we get the total no of female students studying MIS as well as the total no of male students studying MIS.
therefore percentage of the female students in the mis class is:-
[0.05(100-x)]/[0.05(100-x)+0.12x]
while solving, x will be cancelled and the percentage can be obtained.

final answerc

still i am nt happy by this type of questions coz they are poorly worded and rather preparing students for prep for GMAT they are pegging up the students.
_________________

Prepositional Phrases Clarified|Elimination of BEING| Absolute Phrases Clarified
Rules For Posting
www.Univ-Scholarships.com

1 KUDOS received
Intern
Intern
avatar
Joined: 03 Feb 2011
Posts: 12
Followers: 0

Kudos [?]: 1 [1] , given: 0

Re: m04 #04 [#permalink] New post 28 Mar 2011, 01:42
1
This post received
KUDOS
rajeshaaidu wrote:
karthikp1211 wrote:
@rajeshaaidu : We are talking about the Total number of male students and female students in seperate here.With refence to the post above,the second case assumes the values M = 1 and F = 2.So the Total number of female students are 200 and the male students will still be 100.
So the Males in MIS will be 12 percent of 100 as explained.


How we could take seperatly? It's given total number of student enrolled in the MIS and not the total number of female or male student enrolled in the college. so the assumption taken by getting the answer as E is doubtful.


Let me explain you...

Suppose you consider the total number of students as 100. Statement 1 does not mean that 5% (i.e 5) of them are males. It says 5% of the total male students and not the Total students, which is the reason why the seperate totals are considered here...Hope this clears the air...
1 KUDOS received
Verbal Forum Moderator
Verbal Forum Moderator
User avatar
Joined: 15 Jun 2012
Posts: 992
Location: United States
Followers: 112

Kudos [?]: 1096 [1] , given: 118

Re: m04 #04 [#permalink] New post 01 Apr 2013, 23:04
1
This post received
KUDOS
amitbharadwaj7 wrote:
C should be the answer.
If 100 is total no. of Students in W Univesity,
a) then there are 5 nos. of students who are women and MIS student and
b) there are 12 nos. of Students who are men

So 5 / (5+17) is ratio of women to total students who are pursuing MIS in W University. Hence we need both the statements to answer the question.
The answer is C


I think your answer is not correct.

Statement 1 says: 5% of Female students study MIS, not 5% of TOTAL students are Female & study MIS. For instance, there are 100 students, 40 are female, and 5% of 40 is 2 students.

Statement 2: 12% of Male students study MIS, not 12% of TOTAL students are MALE & study MIS.

E is correct. The question is tricky because we only know 5% of F, and 12% of M, but we don't know the ratio between F and M.

For example:
1000 Students, 400F, 600M. So 5% of 400 = 20, 12% of 600 = 72 --> % F & MIS = 20/(20 + 72) = 21.7%
1000 students, 500F, 500M. So 5% of 500 = 25, 12% of 500 = 60 --> % F & MIS = 25/(25 + 60) = 29.4%

Hope it's clear.
_________________

Please +1 KUDO if my post helps. Thank you.

"Designing cars consumes you; it has a hold on your spirit which is incredibly powerful. It's not something you can do part time, you have do it with all your heart and soul or you're going to get it wrong."

Chris Bangle - Former BMV Chief of Design.

Expert Post
1 KUDOS received
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 18737
Followers: 3243

Kudos [?]: 22384 [1] , given: 2616

Re: m04 #04 [#permalink] New post 02 Apr 2013, 01:47
1
This post received
KUDOS
Expert's post
What percent of the MIS students enrolled at Wisconsin University are female?

We want to calculate \frac{MIS_{female}}{MIS_{female}+MIS_{male}}

(1) 5% of female students at Wisconsin University are studying MIS. If there are total of X female students at Wisconsin University then 0.05X=MIS_{female}. Not sufficient.

(2) 12% of male students at Wisconsin University are studying MIS. If there are total of Y male students at Wisconsin University then 0.12Y=MIS_{male}. Not sufficient.

(1)+(2) \frac{MIS_{female}}{MIS_{female}+MIS_{male}}=\frac{0.05X}{0.05X+0.12Y}, still not sufficient to calculate the desired ratio.

Answer: E.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

Get the best GMAT Prep Resources with GMAT Club Premium Membership

Intern
Intern
avatar
Joined: 23 Apr 2009
Posts: 1
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: m04 #04 [#permalink] New post 23 Apr 2009, 04:13
Hi guys,

I don't fully understand the reply.
The question stem asks for a percentage, so a ratio, right?
Then you COULD answer the question with S.1 AND S.2 together.

Let's take the explanation above:
IF the total number of uni students is 2000, you know 100 of them are female MIS and 240 are male MIS. Then the total is 340. So 100/340 * 100 = 29.41... %

Now you can say you DON'T know the number of students of the whole university, that's true but that doesn't matter cause let's say there are 1000 students then the numbers will be: 50 female MIS, 120 male MIS, so the ratio becomes 50/170. (This multiplying by 100 gives the same 29.41... percentage.

Finally the most simple way to dissolve this problem is you know the percentage of the MIS students. 5/12, then you know that the "total" makes 17 and then all you have to do is divide 5 by the "total" of 17.

So in my opinion the answer should be C.
Director
Director
User avatar
Joined: 01 Apr 2008
Posts: 909
Schools: IIM Lucknow (IPMX) - Class of 2014
Followers: 13

Kudos [?]: 190 [0], given: 18

GMAT Tests User
Re: m04 #04 [#permalink] New post 24 Apr 2009, 11:25
Should be C.
From 1 and 2 we can get the number of males+females studying MIS. Then we are done, we can get the percentage of MIS students who are females.

Any takers?
CEO
CEO
User avatar
Joined: 29 Aug 2007
Posts: 2501
Followers: 51

Kudos [?]: 484 [0], given: 19

GMAT Tests User
Re: m04 #04 [#permalink] New post 14 May 2009, 18:25
suyashjhawar wrote:
What percent of the MIS students enrolled at Wisconsin University are female?

1.5% of female students at Wisconsin University are studying MIS.
2.12% of male students at Wisconsin University are studying MIS.

How is the solution (E)?Is'nt it (A) as the first statement is stating what exactly the ques is asking?what am i missing guys?


Similar to this question was discussed many times earlier. One of those discussion is here: settings-57078.html?highlight=motorists
_________________

Verbal: new-to-the-verbal-forum-please-read-this-first-77546.html
Math: new-to-the-math-forum-please-read-this-first-77764.html
Gmat: everything-you-need-to-prepare-for-the-gmat-revised-77983.html


GT

Manager
Manager
avatar
Joined: 30 Jan 2010
Posts: 69
Followers: 2

Kudos [?]: 8 [0], given: 16

GMAT ToolKit User
Re: m04 #04 [#permalink] New post 23 Mar 2010, 05:17
I agree with Sosso, should be C no ?
I also find 29.41..%

By the way this is my first post, happy to be here :-D
Manager
Manager
avatar
Joined: 30 Jan 2010
Posts: 69
Followers: 2

Kudos [?]: 8 [0], given: 16

GMAT ToolKit User
Re: m04 #04 [#permalink] New post 23 Mar 2010, 07:04
ok thanks sandeep, got it
Intern
Intern
avatar
Joined: 30 Jan 2010
Posts: 13
Followers: 0

Kudos [?]: 0 [0], given: 1

Re: m04 #04 [#permalink] New post 23 Mar 2010, 10:47
then we need to determine F/(F+M) with given statmetns
1) it says if TF is total female student at Wisconsin University
=> F = 0.05TF
with this we cant determine value of F/(F+M)

2) it says if TM is total male student at Wisconsin University
=> M = 0.12TM
again with this we cant determine value of F/(F+M)

now combining both:
F/(F+M) = 0.5TF/(0.05TF+0.12TM)
=> we cant determine value of F/(F+M)

copying sandeep

You can't know the actual number of females, BUT, you can know the % which is what the question is asking.
TF, stands for 100% of the females, and TM stands for 100% of the males, so with this, you can get the % of females in wisconsin enrolled in MIS

F/(F+M) = 0.05(1)/(0.05(1)+0.12(1))
F/(F+M) = 0.05/0.17
F/(F+M) = 29.41%

answer C.
Intern
Intern
avatar
Joined: 09 Sep 2010
Posts: 6
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: m04 #04 [#permalink] New post 09 Sep 2010, 01:49
chouky wrote:
I agree with Sosso, should be C no ?
I also find 29.41..%

By the way this is my first post, happy to be here :-D

me too
I agree with Sosso
Intern
Intern
avatar
Joined: 06 Sep 2010
Posts: 10
Followers: 0

Kudos [?]: 1 [0], given: 0

Re: m04 #04 [#permalink] New post 11 Sep 2010, 20:13
Answer is E..

In both the statements we are unable to find the % of female students in the university and the requirement is to find the % of total students who are females in the university who study MIS.
SVP
SVP
avatar
Joined: 16 Nov 2010
Posts: 1692
Location: United States (IN)
Concentration: Strategy, Technology
Followers: 30

Kudos [?]: 275 [0], given: 36

GMAT Tests User Premium Member Reviews Badge
Re: m04 #04 [#permalink] New post 26 Mar 2011, 05:04
Let there be M males and W females in Wisconsin University

So we're asked -> Females MIS/(Female MIS + Male MIS)/ = ?

So From (1)

0.5F -> MIS Female, not sufficient

and from (2)

0.12M -> MIS Male, not sufficient

From (1) and (2) -> 0.5F/(0.5F + 0.12M) = ?

which can't be calculated from the given information.

Answer - E
_________________

Formula of Life -> Achievement/Potential = k * Happiness (where k is a constant)

Get the best GMAT Prep Resources with GMAT Club Premium Membership

Manager
Manager
avatar
Status: A continuous journey of self-improvement is essential for every person -Socrates
Joined: 02 Jan 2011
Posts: 72
Followers: 1

Kudos [?]: 2 [0], given: 14

Re: m04 #04 [#permalink] New post 27 Mar 2011, 20:47
gmatbull wrote:
It has to be E.


Let 100F = total females in Wisconsin University
Let 100M = total males in Wisconsin University

stmt1:
=> 5F are in MIS Dept.
No info about men, so INSUFF

stmt2:
=> 12M are in MIS Dept
No info about females, so, INSUFF

Combining 1&2:
females in MIS = 5F
Males in MIS = 12M
females/total students = 5F/(12M+5F)
we don't know the relative values of F and M. So, INSUFF.

Examples:
case 1:
Let F = M = 1;
i.e Females in MIS = 5
Males in MIS = 12
ratio = 5/(12+5) = 29%

case 2:
Let F = 2; and M = 1.
females in MIS = 10; males in MIS = 12; Put 12% i.e 24 and check
ratio = 10/(12+10) = 10/22
= 45%

29 IS NOT EQUAL TO 45%.
Therefore, the correct response should be E.


I don't agree with you. In the second case how you can take males in MIS=12? In the first case you have taken total number of student to be 100 then number of female=5 and male=12. Similarly, if you double the number of student to be 200 then number of female student should be 10 and male=24 and not 12, because you have to calculate 12% of total number. This will again give 29%. So, the answer should be C. Can you explain where I am going wrong?
Re: m04 #04   [#permalink] 27 Mar 2011, 20:47
    Similar topics Author Replies Last post
Similar
Topics:
m04 bibha 1 12 Jul 2010, 03:49
7 Experts publish their posts in the topic M04 #1 dczuchta 26 22 Sep 2008, 18:48
15 Experts publish their posts in the topic M04 # 32 dczuchta 15 22 Sep 2008, 18:43
3 Experts publish their posts in the topic m04 Q23 vishy007 12 14 Sep 2008, 05:12
22 Experts publish their posts in the topic M04 #12 Tvisha 93 10 Aug 2008, 11:56
Display posts from previous: Sort by

m04 #04

  Question banks Downloads My Bookmarks Reviews Important topics  

Go to page    1   2    Next  [ 35 posts ] 

Moderators: Bunuel, WoundedTiger



GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.