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m04 Q2 : Retired Discussions [Locked]
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U r correct. It can be 1 or 0 in each statement and both statements together.
Since we cant COME TO A CONCLUSION IF ITS EVEN(0) OR ODD(1) its INSUFF
Well my point exactly (although we come to a different conclusion at that). Considering that we don't really need a specific value in this question so long as we can determine whether N is even or not right?
A = Statement 1 is sufficient while Statement 2 is not sufficient. B = Statement 2 is sufficient while Statement 1 is not sufficient C = Statements 1 and 2 together are sufficient while NEITHER statement ALONE is sufficient D = Both Statements 1 and 2 are sufficient (independent of the other) E = Together, Statements 1 and 2 are NOT sufficient.
The answer cannot be D because when Statement 1 is Insufficient, the only possible answer choices left is B, C or E. D is not even an option because A requires #1 to be sufficient and D requires #1 to be sufficient independently of #2.
#1 is insufficient because N^2 will only be equal to N when N = 0 or +1. Because of this, we do not know if N is even because 0 is even, but +1 is odd.
I believe the answer should be E because # is insufficient also.
N could be 1, 0 or even -1. Same thing as #1...even & odd possibilities means that we cannot give a definite answer.
Together will not help because we have 0 and 1 as options for both Statements.
Is integer integer N even?
1. N^2 = N 2. N = N^3
My answer is D but the answer from the system is E, how is this possible?
Both statement will give us 1 or 0 in which neither is even and it's sufficient to answer the problem.
Someone please enlighten me
------------------------------------ J Allen Morris **I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.