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m05 Q17 Probability/Combination

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Kudos [?]: 194 [0], given: 171

Re: m05 Q17 Probability/Combination [#permalink] New post 18 Nov 2012, 01:42
Approach 1: Find the total number of combinations = 2^5=32. Find the number of combinations when Kate wins: out of 5 games, she can win 3 or 4 times only as 5 victories would put her over the $14 mark and less than 3 victories, below the $10.

The number of combinations for winning 3 times:

5C3=10

Number of combinations for winning 4 times:

5C4=5

Remember, nCk=n! / k!∗(n−k)!.

Probability equals 5+1032=1532.

Approach 2: write out the combinations:

[3] : 123, 124, 125, 134, 135, 145, 234, 235, 245, 345

[4] : 1234, 1235, 1245, 1345, 2345

Total: 1532.

The combinations can be summed because they have equal probabilities of 132 each.


The correct answer is B
_________________

Thanks,
PraPon

VOTE: vote-best-gmat-practice-tests-excluding-gmatprep-144859.html
Tough RCs: Passage1 | Passage2 | Passage3 | Passage4 | Passage5 | Passage6 | Passage7

Re: m05 Q17 Probability/Combination   [#permalink] 18 Nov 2012, 01:42
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