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m06 Q20

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m06 Q20 [#permalink] New post 12 Apr 2011, 02:56
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Hi

For this question, I calculated as follows :

5^(root(2)) * 5^(root(2))

= 5^(2root(2))

= 25(root(2))

Is the above approach correct ? Also, where can I learn more about such tricky exponent stuff ?

Regards,
Subhash
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Re: m06 Q20 [#permalink] New post 12 Apr 2011, 03:09
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subhashghosh wrote:
Hi

For this question, I calculated as follows :

5^(root(2)) * 5^(root(2))

= 5^(2root(2))

= 25(root(2))

Is the above approach correct ? Also, where can I learn more about such tricky exponent stuff ?

Regards,
Subhash


Yes, the approach is correct.

(5^{\sqrt{2}})^2=(5^{2})^{\sqrt{2}}=25^{\sqrt{2}} [Note: (x^m)^n=x^{mn}=(x^n)^m]

I think GMAT Club Math book exponents in number theory did a decent job.
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Re: m06 Q20 [#permalink] New post 13 Apr 2011, 10:48
yea, i would be happy to find that kind of practice if someone have it.

thanks.
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Re: m06 Q20 [#permalink] New post 15 Apr 2011, 15:47
Looks alright to me.

I got 25^(sqrt(2)) too.

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Re: m06 Q20   [#permalink] 15 Apr 2011, 15:47
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