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M07q15

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M07q15 [#permalink] New post 04 Jun 2009, 21:13
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At Springfield High, three-fourths of the male students and one-half of the female students speak a foreign language. If there are two-thirds more males than females, what fraction of the students speak a foreign language?



Explanation of this question translates number of male=2/3f (f being the number of females)

I think we cannot translate 2/3 more males than females to 2/3f

It can only be m=2/3*m i.e. f=1/3m.


Am I missing something here?
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Re: #15 M07 [#permalink] New post 05 Jun 2009, 10:56
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I'm not positive but to me, it sounds like this: two-thirds more males than females -> e.g. assume there are 90 students... if there are 2/3 more males than females, then there are 60 more males than females, so 90 = #females + 60 + #females
30 = 2* # females

females = 15
males = 75

So the # of females would actually be 1/5 the number of males.
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Re: #15 M07 [#permalink] New post 10 Jul 2009, 14:42
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I believe OP is correct. There seems to be an issue with the problem.

2/3 more males than females should translate to m = (5/3)f. Indeed, based on just the wording, we should expect to have a greater number of males than females.

Looking at the OA, the table shows fewer males than females, and based on the above that is incorrect.
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Re: #15 M07 [#permalink] New post 11 Jul 2009, 12:23
We'll look into and correct the problems.


Thanks!
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Re: M07q15 [#permalink] New post 27 Jul 2009, 07:18
The question is reworded to the following:

Quote:
At Springfield High, three-fourths of the male students and one-half of the female students speak a foreign language. If the number of males is two-thirds the number of females, what fraction of the students speak a foreign language?

(C) 2008 GMAT Club - m07#15

* \frac{1}{3}
* \frac{2}{3}
* \frac{1}{2}
* \frac{4}{3}
* \frac{3}{5}


Please tell me if yo still see any problems with it. +1 to you, guys, btw.
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Re: M07q15 [#permalink] New post 28 Jul 2009, 14:22
I think ans is OB = 3/5
we know ... Foreign speaking male (3/4M) and female (1/2F)
the number of males is two-thirds the number of females = M=2/3 F or F = 3/2 M

hence [3/4M + 1/2*3/2 M] / [M+3/2M] = 3/5
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Re: M07q15   [#permalink] 28 Jul 2009, 14:22
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