m08 Q 33 : Retired Discussions [Locked]
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# m08 Q 33

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Intern
Joined: 13 Jan 2010
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04 Aug 2010, 09:17
In what proportion should a 30%-solution and a 3%-solution be mixed to obtain a 12%-solution?

1:3
1:2
2:3
3:4
4:5

Please can someone help solve this problem. Also if you can share any tips to solve mixture problemns it will help. I seem to get confused or thrown off with the percentages.
Intern
Joined: 05 Jul 2010
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04 Aug 2010, 09:56
2
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(C-B):(A-C) is actually the ratio of A:B that we need to obtain C.

In this case (12-3):(30-12) => 9:18 => 1:2

Hope this will help.
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Intern
Joined: 13 Jan 2010
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Kudos [?]: 6 [0], given: 10

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04 Aug 2010, 10:02
Thanks for the info. Would you use this relationship to solve most of the mixture problems?
Intern
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04 Aug 2010, 10:23
1
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I guess that it's ideal for this sort of questions. It may not be helpful in solving other problems.
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Re: m08 Q 33   [#permalink] 04 Aug 2010, 10:23
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# m08 Q 33

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