Sachin9 wrote:

1 gives us

y=0 or y=1

2 gives us the same.

Had 2 resulted in y=0 or y=2, would the answer have been C? cause y=0 is common in both statements ?

Please,

DO NOT post pictures of questions. Rule #6 here:

rules-for-posting-please-read-this-before-posting-133935.htmlWhat is the value of y?(1)

y^3+2y=y+2y^2. Rearrange and factor out

y to get

y(y^2-2y+1)=0, which is the same as

y(y-1)^2=0, so

y=0 or

y=1. Not sufficient.

(2)

y^2=y. The same two solutions:

y=0 or

y=1. Not sufficient.

(1)+(2) Nothing new. Not sufficient.

Answer: E.

As for your question: if from (2) we had that y=0 or y=2, then the answer would be C: y=0.

Sorry Sir, Will adhere to rule 6 going forward.

Thanks for the reply..