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10 Feb 2013, 04:27
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1 gives us
y=0 or y=1
2 gives us the same.
Had 2 resulted in y=0 or y=2, would the answer have been C? cause y=0 is common in both statements ?
y=0 or y=1
2 gives us the same.
Had 2 resulted in y=0 or y=2, would the answer have been C? cause y=0 is common in both statements ?
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10 Feb 2013, 04:35
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Sachin9
Please, DO NOT post pictures of questions. Rule #6 here: rules-for-posting-please-read-this-before-posting-133935.html
What is the value of \(y\)?
(1) \(y^3+2y=y+2y^2\). Rearrange and factor out \(y\) to get \(y(y^2-2y+1)=0\), which is the same as \(y(y-1)^2=0\), so \(y=0\) or \(y=1\). Not sufficient.
(2) \(y^2=y\). The same two solutions: \(y=0\) or \(y=1\). Not sufficient.
(1)+(2) Nothing new. Not sufficient.
Answer: E.
As for your question: if from (2) we had that y=0 or y=2, then the answer would be C: y=0.
10 Feb 2013, 04:58
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Bunuel
Sorry Sir, Will adhere to rule 6 going forward.
Thanks for the reply..
Had 2 resulted in y=3 or y=4, answer would have been E ?
