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  M23 #35 [#permalink]
PostPosted: Fri Aug 29, 2008 9:59 am 
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If x is a positive integer, f(x) is defined as the number of positive integers which are less than x and do not have common factor with x other than 1. If x is prime then f(x) = ?

(A) x - 2
(B) x - 1
(C) \frac{x + 1}{2}
(D) \frac{x - 1}{2}
(E) 2

[Reveal] Spoiler: OA
B

Source: GMAT Club Tests - hardest GMAT questions


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  Re: m23 # 35 [#permalink]
PostPosted: Fri Aug 29, 2008 9:59 am 
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i disagree with teh OA. just want to get an opinion


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  Re: m23 # 35 [#permalink]
PostPosted: Fri Aug 29, 2008 11:13 am 
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x-2 for me !


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  Re: m23 # 35 [#permalink]
PostPosted: Fri Aug 29, 2008 11:19 am 
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sset009 wrote:
i disagree with teh OA. just want to get an opinion


I will go with B.
X is prime number..

value <x are
1.2... x-1

there are x-1 integers that are less than x

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  Re: m23 # 35 [#permalink]
PostPosted: Fri Aug 29, 2008 11:20 am 
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stallone wrote:
x-2 for me !


Show me your work.. how did you get x-2

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  Re: m23 # 35 [#permalink]
PostPosted: Fri Aug 29, 2008 3:48 pm 
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i was thinking of x = 3

the number of numbers below three that do not have a any factor apart from 1 is 2
since 1 has a factor of 1 itself, it doenst count.
therefore, f(x3) = 1

similarily, f(2) = 0


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  Re: M23 #35 [#permalink]
PostPosted: Tue Aug 04, 2009 7:47 pm 
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The answer is wrong. OA should be (A).

f(2) = 0 = 0 numbers
f(3) = 2 = 1 number
f(5) = 2,3,4 = 3 numbers
f(7) = 2,3,4,5,6 = 5 numbers
f(x) = x-2 numbers


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  Re: M23 #35 [#permalink]
PostPosted: Wed Aug 05, 2009 5:48 pm 
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bipolarbear wrote:
The answer is wrong. OA should be (A).

f(2) = 0 = 0 numbers
f(3) = 2 = 1 number
f(5) = 2,3,4 = 3 numbers
f(7) = 2,3,4,5,6 = 5 numbers
f(x) = x-2 numbers


bipolar u're forgetting 1.
u need to count 1 as well.
hence f(2) = 1
f(3) = 1,2 -> 2
f(4) = 1,2,3 -> 3

i got this exact question on the gmatprep and answer is x-1.


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  Re: M23 #35 [#permalink]
PostPosted: Wed Aug 05, 2009 5:54 pm 
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viperm5 wrote:
bipolarbear wrote:
The answer is wrong. OA should be (A).

f(2) = 0 = 0 numbers
f(3) = 2 = 1 number
f(5) = 2,3,4 = 3 numbers
f(7) = 2,3,4,5,6 = 5 numbers
f(x) = x-2 numbers


bipolar u're forgetting 1.
u need to count 1 as well.
hence f(2) = 1
f(3) = 1,2 -> 2
f(4) = 1,2,3 -> 3



i got this exact question on the gmatprep and answer is x-1.



but the question states f(x) = number of factors OTHER than 1, so you can't count one... but i guess if gmatprep says so

am i just interpreting the question wrong?


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  Re: M23 #35 [#permalink]
PostPosted: Wed Aug 05, 2009 6:04 pm 
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bipolarbear wrote:
viperm5 wrote:
bipolarbear wrote:
The answer is wrong. OA should be (A).

f(2) = 0 = 0 numbers
f(3) = 2 = 1 number
f(5) = 2,3,4 = 3 numbers
f(7) = 2,3,4,5,6 = 5 numbers
f(x) = x-2 numbers


bipolar u're forgetting 1.
u need to count 1 as well.
hence f(2) = 1
f(3) = 1,2 -> 2
f(4) = 1,2,3 -> 3



i got this exact question on the gmatprep and answer is x-1.



but the question states f(x) = number of factors OTHER than 1, so you can't count one... but i guess if gmatprep says so

am i just interpreting the question wrong?



i fell for the wording too

f(x) defined as all numbers positive less than x AND do not have same factor with x other than 1....meaning that you DO include x.....

do NOT have ...OTHER THAN 1 - means you include 1.


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  Re: M23 #35 [#permalink]
PostPosted: Wed Aug 05, 2009 6:39 pm 
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ah i see it now... this is a tricky gmat problem and even if its part of gmatprep, i think its more of a verbal question than math 8-)


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  Re: M23 #35 [#permalink]
PostPosted: Wed Mar 10, 2010 12:48 pm 
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Ans should be x-1


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  Re: M23 #35 [#permalink]
PostPosted: Wed Mar 10, 2010 5:58 pm 
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Answer should be B.... Need to include '1'.


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  Re: M23 #35 [#permalink]
PostPosted: Wed Mar 10, 2010 8:19 pm 
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Ans:A

f(2) = 0 = 0 numbers
f(3) = 2 = 1 number
f(5) = 2,3,4 = 3 numbers
f(7) = 2,3,4,5,6 = 5 numbers
f(x) = x-2 numbers
if Ans is b then
f(2) = 1 = 1 numbers
f(3) = 2 = 2 number
f(5) = 4 = 4 numbers
f(7) = 6 = 6 numbers
f(x) = x-1 numbers all numbers other then 1 is having comman factor 2 with x and it is given that x is do not have common factor with f(x)

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  Re: M23 #35 [#permalink]
PostPosted: Fri Mar 12, 2010 8:25 pm 
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Kudos (?): 6 (0), given: 7

Plug in 23 for x, f(x) = 22
Plug in another prime 37, f(x) = 36

Ans B

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  Re: M23 #35 [#permalink]
PostPosted: Fri Mar 12, 2010 9:54 pm 
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I also fell for the wording and chose x-2 (A), but now I also agree that the ans should be x-1 or B.


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  Re: M23 #35 [#permalink]
PostPosted: Sat Mar 13, 2010 4:05 am 
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yup, (x-2) was confusing until I read the question again and figured out that I could use 1.
(x-1) it is.

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