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[quote="just4u1530"]Could you pls help with these questions.

1 ) -

(x^2-5x-1)^2 - 25 = (x-a) * (x-b) * (x-c) * (x-d). What is the value of

abcd?

2. is xyz > 0

a. xy > 0 ; b. yz > 0

3. A committe of 4 will be selected out of 6 men and 2 women. How many such commities can be there so that atleast 1 woman will be present.

4. is the range for these numbers greater than 2?

3,4,5,5,x?

a. the median is greater than the avg.

b. the median is 4

Thanks a lot friends[/quote]

The first one, as everyone correctly pointed out, is -24.

However, you can skip 1 step. Since you know that abcd is the coefficient without any x term, you can simply multiply the constants when you've broken them down into the two quadratic multiples.

For #3, I did:

(2C2 x 6C2) + (2C1 x 6C3) = 55

#4:

if x is 10, then the median is smaller than the average, if x is 4, the median is still smaller than the average so st1 is INSUFF

st2 is also INSUFF because for median to be 4, the number has to be 4 and below.

combining statement 1 and 2 leaves us with the numbers 1,2,3 - however, you can't pick 3 because then the median will equal the average.

S1: X could be 2. Which means the avg is 19/5 thus less than 4 (which is the median. This means the range is greater than 2.

Or X could be 5 which means the avg is 22/5 thus less than 5 (which is the median)

Insuff.

S2: X could be 2 or 3.

Insuff.

1&2:

X cannot be 3 or the mean = median. Any number less than 3 gives a mean less than the mean. X cannot be greater than 3 b/c 4 would no longer be the median.

So x<3. this means that the range is greater than 2.