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23 Feb 2023, 02:30
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
72% (01:53) correct
28%
(02:13)
wrong
based on 96
sessions
History
Date
Time
Result
Not Attempted Yet
What is the value of P in the equation \(2x^2 – 33x + P = 0\) given one root is 10 times the other?
A. 20
B. 25
C. 30
D. 35
E. 45
A. 20
B. 25
C. 30
D. 35
E. 45
23 Feb 2023, 06:34
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\(2x^2 - 33x +P = 0\)
let one root be m then the other root is 10m.
sum of roots =\( m +10m =11m = -(-\frac{33}{2}) = \frac{33}{2}\)
or m =\( \frac{3}{2}\)
product of roots = \(10m^2 \)= \(\frac{P}{2}\)
=> \(10*\frac{9}{4} = \frac{P}{2}\)
=> P = 45
Answer E
let one root be m then the other root is 10m.
sum of roots =\( m +10m =11m = -(-\frac{33}{2}) = \frac{33}{2}\)
or m =\( \frac{3}{2}\)
product of roots = \(10m^2 \)= \(\frac{P}{2}\)
=> \(10*\frac{9}{4} = \frac{P}{2}\)
=> P = 45
Answer E
General Discussion
01 Apr 2023, 06:39
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Hello,
I am not sure why we have a minus in front of the brackets in the second step "11m=−(−33/2)"
Can somebody tell me?
Thank you in advance !
I am not sure why we have a minus in front of the brackets in the second step "11m=−(−33/2)"
Can somebody tell me?
Thank you in advance !
