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gmatophobia
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Why did we group the first 4 digits together and the last 3 together/only rearrange them within their own groups, instead of rearranging all 7? Is there something that indicates this in the question? I'm also confused about how to figure out the different patterns.
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Thank you Bunuel ..That's wonderfully explained..
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user1592
A certain computer program reorders the letters of any seven-letter sequence, and the position of a letter in the new order depends only on its position in the original order. The first run of the program changes the initial input ABCDEFG to the output DABCGEF. If the input to each subsequent run is the output from the preceding run, after how many runs will the output first equal the initial input ABCDEFG ?

A. 6
B. 7
C. 12
D. 14
E. 24

Why did we group the first 4 digits together and the last 3 together/only rearrange them within their own groups, instead of rearranging all 7? Is there something that indicates this in the question? I'm also confused about how to figure out the different patterns.

The question says that the position of a letter in the new order depends only on its position in the original order. Then we are told that ABCDEFG was reordered to DABCGEF.

    ABCDEFG
    DABCGEF

Observe that in the first four letters, ABCD, the change was that the first three letters and the fourth letters were switched: ABCD became DABC. In the last three letters, EFG, the first two letters and the third letter were switched: EFG became GEF.

Hence, the first four letters would change the following way:

ABCD - The initial order
  1. DABC
  2. CDAB
  3. BCDA
  4. ABCD - Back to the initial order

The last three letters would change the following way:

EFG - The initial order.
  1. GEF
  2. FGE
  3. EFG - Back to the initial order

As we can see, the first four letters cycle back to the initial order after every 4 runs and the last three letters cycle back to the initial order after every 3 runs. Therefore, the entire word will cycle back to the initial order of ABCDEFG in 12 runs:

ABCD - EFG - The initial order
  1. DABC - GEF
  2. CDAB - FGE
  3. BCDA - EFG
  4. ABCD - GEF
  5. DABC - FGE
  6. CDAB - EFG
  7. BCDA - GEF
  8. ABCD - FGE
  9. DABC - EFG
  10. CDAB - GEF
  11. BCDA - FGE
  12. ABCD - EFG - Back to the initial order

Answer: C.­
­
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KarishmaB I had no clue how to solve and approach this question. Any similar questions? Do you have this topic in your content?
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Detailed video solution




IMO C

Smart Prep
gmatophobia
A certain computer program reorders the letters of any seven-letter sequence, and the position of a letter in the new order depends only on its position in the original order. The first run of the program changes the initial input ABCDEFG to the output DABCGEF. If the input to each subsequent run is the output from the preceding run, after how many runs will the output first equal the initial input ABCDEFG ?

A. 6
B. 7
C. 12
D. 14
E. 24

Attachment:
IMG-20231119-WA0000.jpg
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KarishmaB I had no clue how to solve and approach this question. Any similar questions? Do you have this topic in your content?

The question is an application of functions and sequences (an iterative user defined operator)

Think about this: We see repeating sequences at times such as: 4, 3, -2, 1, 4, 3, -2, 1, ...
We obtain each next term by performing same operation on some previous terms.

This question is the same. First value is ABCDEFG. We obtain the next one by picking the 4th letter and bringing it to the front and picking the last letter and placing it after the first 4 letters. DABCGEF
Next, again we will do the same thing. We will get CDABFGE

Look at the pattern as we do in sequences. First 4 letters are moving in a circular manner and last 3 are moving in a circular manner. So after the 12th step, cycles of both will be over.

I have discussed such sequences in my content.
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Very interesting problem. It's really just a two part cycle, and you have to find where they will coincide again, which is on the LCM:

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gmatophobia
A certain computer program reorders the letters of any seven-letter sequence, and the position of a letter in the new order depends only on its position in the original order. The first run of the program changes the initial input ABCDEFG to the output DABCGEF. If the input to each subsequent run is the output from the preceding run, after how many runs will the output first equal the initial input ABCDEFG ?

A. 6
B. 7
C. 12
D. 14
E. 24

Attachment:
IMG-20231119-WA0000.jpg
We have to find the pattern in this first.

Input : A B C D E F G
Output : D A B C G E F

Subsequent outputs:
C D A B F G E
B C D A E F G

It's clear that the first 4 letters are rotating in a separate cycle and the last 3 letters are rotating in a separate cycle.

So the number of runs it takes them to reach the initial output, or reach the same starting point is the LCM of 4 and 3, i.e, 12.

Answer: 12 (C)
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KarishmaB

i understood everything except the part that why i need to take lcm of 4 and 3 here, this is still confusing me to be honest.
KarishmaB


Important thing is to identify the pattern. For that, we need to write down the first few steps. I wrote down the positions and then changed them at every step.

1234567

Step 1: 4123756
Step 2: 3412675
Step 3: 2341567 (Last 3 digits are back in their place)
Step 4: 1234756 (First 4 digits are back in their place but last 3 are now messed up)
...

The first digits will follow a cycle of 4 steps and will be back in original order after 4 steps. The last 3 digits will follow a cycle of 3 steps and will be back in order after 3 steps. So both will be back in order for the first time after 12 steps - the LCM of 4 and 3.

Answer (C)

Pattern recognition is an important skill one must develop for GMAT. Here is another question that needs pattern recognition: https://anaprep.com/arithmetic-pattern- ... roperties/
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After every 4 steps, the first 4 digits are back in their place.
This means that first 4 digits will be in their place after every 4 steps or 8 steps or 12 steps or 16 steps etc.
After every 3 steps, the last 3 digits are back in their place.
This means that last 3 digits will be in their place after every 3 steps or 6 steps or 9 steps or 12 steps etc.

So all digits will be back in their place after 12 steps. So essentially, we have taken the LCM of 3 and 4.

lawyeroffduty
KarishmaB

i understood everything except the part that why i need to take lcm of 4 and 3 here, this is still confusing me to be honest.

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