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ekwok

Given: The revenue of a small company increased from x dollars in 2000 to z dollars in 2002.

Asked: If the percent increase in the company's revenue from 2000 to 2001 was equal to the percent increase in the company's revenue from 2001 to 2002, what was the company's revenue in 2001 in terms of x and z?

Let the company's revenue in 2001 be y

y/x = z/y
y^2 = xz
\(y = \sqrt{xz}\)

IMO D
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Let's denote the company's revenue in 2000 as \(x\) dollars, the revenue in 2001 as \(y\) dollars, and the revenue in 2002 as \(z\) dollars.

The percent increase from 2000 to 2001 is given by:

\[ \text{Percent Increase from 2000 to 2001} = \frac{y - x}{x} \times 100 \]

The percent increase from 2001 to 2002 is given by:

\[ \text{Percent Increase from 2001 to 2002} = \frac{z - y}{y} \times 100 \]

According to the given information, these two percent increases are equal:

\[ \frac{y - x}{x} \times 100 = \frac{z - y}{y} \times 100 \]

Now, let's simplify this equation:

\[ \frac{y - x}{x} = \frac{z - y}{y} \]

Cross-multiply to eliminate the fractions:

\[ y^2 - xy = xz - xy \]

Add \(xy\) to both sides:

\[ y^2 = xz \]

Now, solve for \(y\):

\[ y = \sqrt{xz} \]

So, the company's revenue in 2001 in terms of \(x\) and \(z\) is \(y = \sqrt{xz}\) dollars.
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Bunuel

ekwok
The revenue of a small company increased from x dollars in 2000 to z dollars in 2002. If the percent increase in the company's revenue from 2000 to 2001 was equal to the percent increase in the company's revenue from 2001 to 2002, what was the company's revenue in 2001 in terms of x and z?

(A) \(\frac{(x+z)}{2}\)

(B) \(\frac{xz}{2}\)

(C) \(\frac{(z-x)}{2x}\)

(D) \(\sqrt{xz}\)

(E) \(\sqrt{\frac{(z-x)}{x}}\)
The company's revenue from 2000 to 2002 increased \(\frac{z}{x}\) times (for example, if the revenue increased from 100 to 400, it increased 400/100 = 4 times).

Assuming the increase from 2000 to 2001, and from 2001 to 2002, was k times, then \(k^2=\frac{z}{x}\), yielding \(k=\sqrt{\frac{z}{x}}\) (for example, if the revenue from 2000 to 2002 increased 4 times, and the increase from 2000 to 2001, and from 2001 to 2002, was the same, then each year the revenue increases twice, (from \(k^2=4\), we get (\(k=2\))).

Hence, the revenue in 2001 was \(x*\sqrt{\frac{z}{x}}=\sqrt{\frac{x^2z}{x}}=\sqrt{xz}\).

Answer: D.
­Hey Bunuel, could you please link some other questions similar to this ? :)
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Bunuel

ekwok
The revenue of a small company increased from x dollars in 2000 to z dollars in 2002. If the percent increase in the company's revenue from 2000 to 2001 was equal to the percent increase in the company's revenue from 2001 to 2002, what was the company's revenue in 2001 in terms of x and z?

(A) \(\frac{(x+z)}{2}\)

(B) \(\frac{xz}{2}\)

(C) \(\frac{(z-x)}{2x}\)

(D) \(\sqrt{xz}\)

(E) \(\sqrt{\frac{(z-x)}{x}}\)
The company's revenue from 2000 to 2002 increased \(\frac{z}{x}\) times (for example, if the revenue increased from 100 to 400, it increased 400/100 = 4 times).

Assuming the increase from 2000 to 2001, and from 2001 to 2002, was k times, then \(k^2=\frac{z}{x}\), yielding \(k=\sqrt{\frac{z}{x}}\) (for example, if the revenue from 2000 to 2002 increased 4 times, and the increase from 2000 to 2001, and from 2001 to 2002, was the same, then each year the revenue increases twice, (from \(k^2=4\), we get (\(k=2\))).

Hence, the revenue in 2001 was \(x*\sqrt{\frac{z}{x}}=\sqrt{\frac{x^2z}{x}}=\sqrt{xz}\).

Answer: D.
­Hey Bunuel, could you please link some other questions similar to this ? :)
­
Check the links below:
https://gmatclub.com/forum/m20-184230.html
https://gmatclub.com/forum/m28-184507.html
https://gmatclub.com/forum/m24-184400.html
https://gmatclub.com/forum/m25-184408.html
https://gmatclub.com/forum/m08-183772.html
https://gmatclub.com/forum/m20-184243.html
https://gmatclub.com/forum/m15-184049.html

Hope this helps.
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ekwok

Given: The revenue of a small company increased from x dollars in 2000 to z dollars in 2002.

Asked: If the percent increase in the company's revenue from 2000 to 2001 was equal to the percent increase in the company's revenue from 2001 to 2002, what was the company's revenue in 2001 in terms of x and z?

Let the company's revenue in 2001 be y

y/x = z/y
y^2 = xz
\(y = \sqrt{xz}\)

IMO D
­hi, why are we equating it as y/x? and how do we get the percent increase from it?
 
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let , x = 100 (2000) , 10% increase : y=110 (2001) , 10% increase : z = 121 (2002)

now place the value in the answers and see which gives y = 110 (that's our answer)
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The revenue of a small company increased from x dollars in 2000 to z dollars in 2002. If the percent increase in the company's revenue from 2000 to 2001 was equal to the percent increase in the company's revenue from 2001 to 2002, what was the company's revenue in 2001 in terms of x and z?

(A) \(\frac{x+z}{2}\)

(B) \(\frac{xz}{2}\)

(C) \(\frac{z-x}{2x}\)

(D) \(\sqrt{xz}\)

(E) \(\sqrt{\frac{z-x}{x}}\)­


Let the percent increase from each year to the next equal p.

In that case, we have the following:

\(x(1 + \frac{p}{100})^2 = z\)

Thus, the following is true:

\((1 + \frac{p}{100})^2 = \frac{z}{x}\)

Also, in that case, the value for 2001 is the following:

\(\text{2001 Revenue} = x(1 + \frac{p}{100})\)

\((1 + \frac{p}{100}) = \sqrt{(1 + \frac{p}{100})^2}\)

So, we can say the following:

\(\text{2001 Revenue} = x\sqrt{\frac{z}{x}}\)

\(\text{2001 Revenue} = \sqrt{\frac{x^2z}{x}}\)

\(\text{2001 Revenue} = \sqrt{xz}\)

Correct answer: D
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We are given that the % increase from 2000 to 2001 and from 2001 to 2002 is the same.

Let p be the multiplication factor associated with this % increase.

For example, if the % increase is 10%, then p = 1.1. If the % increase is 30%, then p = 1.3.


Harsha
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The revenue of a small company increased from x dollars in 2000 to z dollars in 2002. If the percent increase in the company's revenue from 2000 to 2001 was equal to the percent increase in the company's revenue from 2001 to 2002, what was the company's revenue in 2001 in terms of x and z?

Percent Change From 2000 to 2002 \(= \frac{z - x}{x} × 100\)

So, \(z = x(1 + \frac{z - x}{x})\).

Thus, 2001 revenue \(= x\sqrt{1 + \frac{z - x}{x}}\).

\(= \sqrt{x^2 + xz - x^2}\)

\(= \sqrt{xz}\)

(A) \(\frac{x+z}{2}\)

(B) \(\frac{xz}{2}\)

(C) \(\frac{z-x}{2x}\)

(D) \(\sqrt{xz}\)

(E) \(\sqrt{\frac{z-x}{x}}\)­


Correct answer: D
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Given information:
Revenue for Year 2000 = x dollars
Revenue for year 2002 = z dollars

Let revenue for year 2001 = y dollars

Given:
\(\frac{y}{x} -1 = \frac{z}{y} - 1\) [ Percentage increase in revenue from year 2000 to 2001 is same as percentage increase in revenue from year 2001 to 2002]
Solve:
\(\frac{y}{x} = \frac{z}{y}\)
\(y^2 = xz\)
\(y = \sqrt{xz } \)

Option D
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Easy to plugin values and check.

Let x = 100 and % increase = 50%

x =100
y = 150
z = 200

Clearly only option D provides us an answer of 150.
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Let's assume that the revenue of 2000, ie. x = 1000$. Therefore, y = 1100$ and z = 1210$. Now we see each option, A/. 2210/2 = 1105, so no. We can already see B is not possible. C. 210/2, again no. D. sqrt 1210000 = 1100. Therefore D is our answer.

I took barely 1.5 mins to solve this question this way, so decided to share it here.
ekwok
The revenue of a small company increased from x dollars in 2000 to z dollars in 2002. If the percent increase in the company's revenue from 2000 to 2001 was equal to the percent increase in the company's revenue from 2001 to 2002, what was the company's revenue in 2001 in terms of x and z?

(A) \(\frac{x+z}{2}\)

(B) \(\frac{xz}{2}\)

(C) \(\frac{z-x}{2x}\)

(D) \(\sqrt{xz}\)

(E) \(\sqrt{\frac{z-x}{x}}\)­


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