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We need to find how many integer values of p and q satisfy
\(3p-q=9\)
\(|q|≤14\)

\(|q|≤14\)
=> -14 ≤ q ≤ 14

­\(3p-q=9\)
=> 3p = 9 + q
=> p = \(\frac{9 + q}{3}\)

For p to be an integer q has to be a multiple of 3

=> Possible values of q between -14 to 14 and which are multiples of 3 are
-12, -9, ..., 9, 12
=> \(\frac{(12 - (-12))}{3}\) + 1 [ Watch this video to learn about Arithmetic Series ]
= 8 + 1 = 9

So, Answer will be B
Hope it helps!

Watch the following video to MASTER Inequality + Absolute value Problems

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