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20 Jan 2008, 22:00
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Lisa invested 1000$ at r% interest compounded semi-annually for one year. Is r greater than 12%?
1. If she had invested the 1000$ at (r+1)% simple interest for one year, she would have received more interest.
2. If she had invested the 1000$ at (r+0.5)% simple interest for one year, she would have received less interest.
1. If she had invested the 1000$ at (r+1)% simple interest for one year, she would have received more interest.
2. If she had invested the 1000$ at (r+0.5)% simple interest for one year, she would have received less interest.
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20 Jan 2008, 22:32
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answer is D
Expl : Its a yes/no question . if we assume r=13% , as per first statement
(r+1)/100 > (1+r/100)^2
so we can find out if true or not , in both cases requirement is met
same for second statement
WHATS OFFICIAL ANSWER
Expl : Its a yes/no question . if we assume r=13% , as per first statement
(r+1)/100 > (1+r/100)^2
so we can find out if true or not , in both cases requirement is met
same for second statement
WHATS OFFICIAL ANSWER
20 Jan 2008, 23:58
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I misunderstand the conditions:
1. \(\frac{(r+1)}{100} > (1+\frac{r}{100})^2\)
\((\frac{r}{100}+\frac{1}{100})> (1+\frac{2r}{100}+(\frac{r}{100})^2)\)
\(0> (\frac{99}{100}+\frac{r}{100}+(\frac{r}{100})^2)\) is always false.
1. \(\frac{(r+1)}{100} > (1+\frac{r}{100})^2\)
\((\frac{r}{100}+\frac{1}{100})> (1+\frac{2r}{100}+(\frac{r}{100})^2)\)
\(0> (\frac{99}{100}+\frac{r}{100}+(\frac{r}{100})^2)\) is always false.
