Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 27 Jun 2016, 02:31

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Permutation and Combination Help!

Author Message
TAGS:

### Hide Tags

Intern
Joined: 16 Mar 2011
Posts: 2
Followers: 0

Kudos [?]: 2 [0], given: 0

### Show Tags

16 Mar 2011, 06:18
3
This post was
BOOKMARKED
Hi, I'm new to this site so forgive me if I violate any rules.

I need help with a P&C question:

A group of 10 people consists of 3 married couples and 4 single men.
A committee of 4 is to be fo from the 10 people.
How many different committees can be formed if the committee can consist of at most 1 married couple?

Would appreciate it if any one of you can reply asap! I need urgent help
GMAT Pill Representative
Joined: 14 Apr 2009
Posts: 1981
Location: New York, NY
Followers: 370

Kudos [?]: 1152 [1] , given: 8

Re: Permutation and Combination Help! [#permalink]

### Show Tags

17 Mar 2011, 14:56
1
KUDOS
Expert's post
3
This post was
BOOKMARKED
Hi yogibearsayshi,

This video might help you understand the breakdown of this "nested GMAT combination" question.

Entwistle --good job breaking down the problem and doing the problem! But watch out! Your calculations were great, but looks like you forgot to get back to the original question and note that they only care about combinations that involve AT MOST 1 couple. I know--GMAT guys do that a lot. I almost missed it too! They make you do this complicated calculation that makes you forget what specific condition they restrict the problem to.

Hope that helps!
_________________
GMAT Pill Representative
Joined: 14 Apr 2009
Posts: 1981
Location: New York, NY
Followers: 370

Kudos [?]: 1152 [1] , given: 8

Re: Permutation and Combination Help! [#permalink]

### Show Tags

18 Mar 2011, 09:14
1
KUDOS
Expert's post
1
This post was
BOOKMARKED
Ah--in that case, the question relies on a critical assumption: that couples don't necessarily stay together.

The analysis above assumes that couples stay together.

But if couples do not stay together, then a lot more possibilities exist:

You can have 1 married person, and 3 singles.
You can have 2 married people, and 2 singles.
You can have 3 married people, and 1 single.
You can have 4 married people (only 2 of them can be a couple, the other 2 cannot).

So this complicates things further. In this case, using the method maliyeci and yogibearsayshi suggested above, you find the total possible combinations and then subtract the 1 case scenario that is prohibited.

So you treat the married people like singles in terms of calculations, but then subtract out the case when there are 2 married couples.

So yes, that would be 10C4 - 3C2.
10C4 because you are selecting from 10 and choosing 4 people (regardless of married/single status).
3C2 because you want the # of people possibilities for 2 married couples that you want to subtract from the overall.

This would give you:
10C4 = 10! / (4! * 6!) = (10*9*8*7) / (4*3*2*1) = (10*3*7) / (1) = 210

3C2 = 3! / (2! * 1*) = 3

210 - 3 = 207

I'm not so sure you'd see a question worded like this on the actual GMAT. The calculation with the factorials is a little bit more in depth than I would expect. But good to go through though.
_________________
Senior Manager
Joined: 05 Jul 2010
Posts: 359
Followers: 15

Kudos [?]: 49 [1] , given: 17

Re: Permutation and Combination Help! [#permalink]

### Show Tags

19 Mar 2011, 12:38
1
KUDOS
I 100% DON'T agree with GMAT Pill Instructor initial assumption!! No where in the question it says you can assume married couple don't split up.

*Here is the solution in simple terms:*
1. All 4 single = 4C4 = 1
2. 1 married couple included = 3C1* (for the rest 2 there are 3 cases: 2 are single + 1 is married*1 is single + 2 are married)
= 3C1* ( 4C2 + (2C1*2)*4C1 + (2C2*2*2) )
= 3 * (6 + 16 + 4) = 3 * 26 = 78
3. 1 married & 3 single = (3C1*2)*4C3 = 24
4. 2 married & 2 single = (3C2*2*2)*4C2 = 12*6=72
5. 3 married & 1 single = (3C3*2*2*2)*4C1 = 8*4=32

Total = 1+ 78 + 24 + 72 + 32 = 207

I might have done some calculation mistake (forgive me for that), but hope you got the point.

*Alternative approach:* (I always thing of negative approach as if you go to harder levels, GMAT I think likes to test this way of your thinking)
At-most 1 married couple
= Total possible ways - 2 married couple
= 10C4 - 3C2
= 210 - 3
= 207

Hope this helps!
Director
Status: -=Given to Fly=-
Joined: 04 Jan 2011
Posts: 834
Location: India
Schools: Haas '18, Kelley '18
GMAT 1: 650 Q44 V37
GMAT 2: 710 Q48 V40
GMAT 3: 750 Q51 V40
GPA: 3.5
WE: Education (Education)
Followers: 48

Kudos [?]: 191 [0], given: 78

Re: Permutation and Combination Help! [#permalink]

### Show Tags

16 Mar 2011, 09:11
Post Edit

Solution provided by me was wrong

Sorry!
_________________

"Wherever you go, go with all your heart" - Confucius

1. How to Review and Analyze your Mistakes (Post by BB at GMAT Club)

2. 4 Steps to Get the Most out out of your CATs (Manhattan GMAT Blog)

My Experience With GMAT

1. From 650 to 710 to 750 - My Tryst With GMAT

2. Quest to do my Best - My GMAT Journey Log

Last edited by AmrithS on 19 Mar 2011, 17:02, edited 1 time in total.
Director
Status: -=Given to Fly=-
Joined: 04 Jan 2011
Posts: 834
Location: India
Schools: Haas '18, Kelley '18
GMAT 1: 650 Q44 V37
GMAT 2: 710 Q48 V40
GMAT 3: 750 Q51 V40
GPA: 3.5
WE: Education (Education)
Followers: 48

Kudos [?]: 191 [0], given: 78

Re: Permutation and Combination Help! [#permalink]

### Show Tags

16 Mar 2011, 09:14
From next time on, post the questions for problem solving in this Forum:

gmat-problem-solving-ps-140/

Welcome to the Club :

_________________

"Wherever you go, go with all your heart" - Confucius

1. How to Review and Analyze your Mistakes (Post by BB at GMAT Club)

2. 4 Steps to Get the Most out out of your CATs (Manhattan GMAT Blog)

My Experience With GMAT

1. From 650 to 710 to 750 - My Tryst With GMAT

2. Quest to do my Best - My GMAT Journey Log

Intern
Joined: 16 Mar 2011
Posts: 2
Followers: 0

Kudos [?]: 2 [0], given: 0

Re: Permutation and Combination Help! [#permalink]

### Show Tags

18 Mar 2011, 01:58
Hey thanks for the help! And I'll take note of that, Entwistle.

However the answer is supposed to be 207. /: I finally figured out the solution, but it doesn't make sense! I used your method to tackle this question as well.

Soln: No. of committees= 10C4-4C3=207
Senior Manager
Joined: 23 Jun 2009
Posts: 353
Location: Turkey
Schools: UPenn, UMich, HKS, UCB, Chicago
Followers: 5

Kudos [?]: 116 [0], given: 63

Re: Permutation and Combination Help! [#permalink]

### Show Tags

18 Mar 2011, 08:08
4 people can be chosen from 10 people in 10C4 = 210 ways. Question only wants us to exclude the last case, 2 couples are in commitee. That is 3C2=3 possibilities.
210-3=207
Director
Status: -=Given to Fly=-
Joined: 04 Jan 2011
Posts: 834
Location: India
Schools: Haas '18, Kelley '18
GMAT 1: 650 Q44 V37
GMAT 2: 710 Q48 V40
GMAT 3: 750 Q51 V40
GPA: 3.5
WE: Education (Education)
Followers: 48

Kudos [?]: 191 [0], given: 78

Re: Permutation and Combination Help! [#permalink]

### Show Tags

19 Mar 2011, 17:01
Damn

Stupid me for not reading the problem properly

Thank you gmatpill!
_________________

"Wherever you go, go with all your heart" - Confucius

1. How to Review and Analyze your Mistakes (Post by BB at GMAT Club)

2. 4 Steps to Get the Most out out of your CATs (Manhattan GMAT Blog)

My Experience With GMAT

1. From 650 to 710 to 750 - My Tryst With GMAT

2. Quest to do my Best - My GMAT Journey Log

Director
Status: Impossible is not a fact. It's an opinion. It's a dare. Impossible is nothing.
Affiliations: University of Chicago Booth School of Business
Joined: 03 Feb 2011
Posts: 920
Followers: 13

Kudos [?]: 299 [0], given: 123

Re: Permutation and Combination Help! [#permalink]

### Show Tags

21 Mar 2011, 13:18
Pls move this to PS Quant forum.
Intern
Joined: 30 Mar 2011
Posts: 48
Schools: Virginia Tech
Followers: 0

Kudos [?]: 2 [0], given: 0

Re: Permutation and Combination Help! [#permalink]

### Show Tags

01 Apr 2011, 15:51
Typically, how many P&C questions will you encounter?
GMAT Pill Representative
Joined: 14 Apr 2009
Posts: 1981
Location: New York, NY
Followers: 370

Kudos [?]: 1152 [0], given: 8

Re: Permutation and Combination Help! [#permalink]

### Show Tags

04 Apr 2011, 10:11
Expert's post
aznboi986 wrote:
Typically, how many P&C questions will you encounter?

Well, the test is adaptive. P&C questions are usually tougher so if you don't answer enough hard questions to get here, then you might not encounter any. However, if you are looking to score in the 700 range, you will likely encounter a few (2 or 3) in varying difficulties. Often times you can think through the variations, but understanding the formula as well as Permutations vs combinations vs variations will help you answer the question quickly and accurately without having a panic during exam time.
_________________
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 10199
Followers: 481

Kudos [?]: 124 [0], given: 0

Re: Permutation and Combination Help! [#permalink]

### Show Tags

27 Jun 2014, 16:11
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 10199
Followers: 481

Kudos [?]: 124 [0], given: 0

Re: Permutation and Combination Help! [#permalink]

### Show Tags

29 Sep 2015, 12:18
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Re: Permutation and Combination Help!   [#permalink] 29 Sep 2015, 12:18
Similar topics Replies Last post
Similar
Topics:
2 Combinations/Permutations 2 30 Nov 2011, 18:08
2 Combinations and Permutations 3 28 Aug 2011, 17:53
Very Helpful Review on Permutations and Combinations 0 09 Jun 2011, 10:16
Combination/Permutation 1 31 May 2011, 13:41
Permutation and Combination Help 2 22 Apr 2011, 10:14
Display posts from previous: Sort by