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Permutation-Sitting Arrangement

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Author Message
TAGS:
Manager
Manager
User avatar
Joined: 19 Feb 2009
Posts: 58
Schools: INSEAD,Nanyang Business school, CBS,
Followers: 2

Kudos [?]: 25 [0], given: 8

Permutation-Sitting Arrangement [#permalink] New post 05 Feb 2010, 12:18
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

100% (01:08) correct 0% (00:00) wrong based on 3 sessions
In how many ways can five girls stand in line if Maggie and Lisa cannot stand next to each other?

(A) 112
(B) 96
(C) 84
(D) 72
(E) 60

OA :
[Reveal] Spoiler:
D

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Expert Post
CEO
CEO
User avatar
Joined: 17 Nov 2007
Posts: 3571
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 367

Kudos [?]: 1848 [0], given: 358

GMAT ToolKit User Premium Member
Re: Permutation-Sitting Arrangement [#permalink] New post 05 Feb 2010, 12:31
Expert's post
1. the total number of permutations: 5! = 120
2. Let's consider Maggie and Lisa as one object, then the total number of permutations with Maggie and Lisa together: 4! = 24.
3. Take into account that [Maggie, Lisa] and [Lisa, Maggie] are different.
4. Maggie and Lisa cannot stand next to each other in: 120 - 2*24 = 72 ways.
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Manager
Manager
User avatar
Joined: 19 Feb 2009
Posts: 58
Schools: INSEAD,Nanyang Business school, CBS,
Followers: 2

Kudos [?]: 25 [0], given: 8

Re: Permutation-Sitting Arrangement [#permalink] New post 05 Feb 2010, 12:52
Got it walker..

Thanks V.Much for this explanation
_________________

Working without expecting fruit helps in mastering the art of doing fault-free action !

Re: Permutation-Sitting Arrangement   [#permalink] 05 Feb 2010, 12:52
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