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problem solving

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Intern
Joined: 07 Aug 2004
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problem solving [#permalink]  10 Aug 2004, 08:42
HI,
I/a a new meber and this is the first time t post a topic here. It's difficult for me so i hope to be helped.
tickets for all but 100 seats in a 10,000 seat stadium were sold. Of the tickets sold, 20% were sold at halt price and the remaining tickets were sold at the full price of \$2. What was the total revenue from tickets sales?
there are five choices:
a. \$15,840
b.\$17,820
c.\$18,000
d.\$19,800
e.\$21,780
thank u.
Senior Manager
Joined: 05 Feb 2004
Posts: 291
Location: USA
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[#permalink]  10 Aug 2004, 09:42
B...

Tickets sold = 10,000 - 100 = 9900

20% tickets were sold at half price which is \$ 1. Hence revenue from this sale = 20/100 *9900*1 = 1980 dollars

rest 80% were sold at full price of 2 dollars. Hence revenue from this sale
= 80/100*9900*2 = 15840

Add both revenues to get = 17820!!
CIO
Joined: 09 Mar 2003
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[#permalink]  10 Aug 2004, 09:47
exactly right. 17,820.

Welcome to the club!
CEO
Joined: 15 Aug 2003
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[#permalink]  10 Aug 2004, 22:54
welcome lapin.

you are most welcome to post any questions you have. dont worry even if it is a simple question. we are all here to help

praetorian
[#permalink] 10 Aug 2004, 22:54
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