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Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of t

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Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of t [#permalink]

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New post 10 Jun 2016, 03:11
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Question Stats:

83% (01:25) correct 17% (01:17) wrong based on 143 sessions

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Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of the tickets sold, 20% were sold at half price and the remaining tickets were sold at the full price of $2. What was the total revenue from ticket sales?

A. $15,840
B. $17,820
C. $18,000
D. $19,800
E. $21,780

The question was locked, so this is a re-post.

What is the quickest way to solve this? I guess rounding is one method. Are there any other methods?
[Reveal] Spoiler: OA
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Re: Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of t [#permalink]

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New post 10 Jun 2016, 07:31
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10000 seats --> Full Price : Half Price = 8000 : 2000
Price when all seats are filled = 16000 + 2000 = 18000

100 seats are unsold --> Loss due to unfilled seats = 20 + 2*80 = 180

Revenue = 18000 - 180 = 17820

Answer: B
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Re: Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of t [#permalink]

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New post 10 Jun 2016, 08:57
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100 are not sold from 10,000

So seats sold=9900

20% is 1980 and remaining 80% is 7920.

each ticket cost 2$ and 1980 cost 1$

So 2*7920 +1980=17820 is ur answer.
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Re: Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of t [#permalink]

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New post 01 Mar 2018, 07:00
bimalr9 wrote:
Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of the tickets sold, 20% were sold at half price and the remaining tickets were sold at the full price of $2. What was the total revenue from ticket sales?

A. $15,840
B. $17,820
C. $18,000
D. $19,800
E. $21,780

The question was locked, so this is a re-post.

What is the quickest way to solve this? I guess rounding is one method. Are there any other methods?



The fastest way to solve it, is to ignore at first the fact that 100 were not sold.

so 20% of 10,000 = 2000

remaining 8000 sold for 2 dollar = 16000

16,000+2000 = 18,000
(now since -100 tickets)

from answer options one can see that the clossest number should be just a bit smaller than 18000

Hence B :)
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Re: Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of t [#permalink]

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New post 02 Mar 2018, 10:34
bimalr9 wrote:
Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of the tickets sold, 20% were sold at half price and the remaining tickets were sold at the full price of $2. What was the total revenue from ticket sales?

A. $15,840
B. $17,820
C. $18,000
D. $19,800
E. $21,780


0.2 x 9,900 = 1,980 tickets were sold for 1 dollar each, so these tickets generated 1,980 dollars in revenue.

9,900 - 1,980 = 7,920 were sold for 2 dollars each, so these tickets generated 15,840 dollars in revenue.

The total revenue earned was 1,980 + 15,840= 17,820 dollars.

Answer: B
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Re: Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of t   [#permalink] 02 Mar 2018, 10:34
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