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# ps - machine

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VP
Joined: 30 Sep 2004
Posts: 1488
Location: Germany
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Kudos [?]: 105 [0], given: 0

ps - machine [#permalink]  27 Dec 2005, 09:37
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A machine's ratio of depreciation is 6/16, 5/16, and 4/16 for the first 3 years. Third year's depreciated amount is \$600 less than first year's depreciated amount. How much is depreciated in the second year?
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Senior Manager
Joined: 05 Jan 2005
Posts: 254
Followers: 1

Kudos [?]: 4 [0], given: 0

Should be 3000

5X/16 - 4X/16 = 600

X/16 = 600

5X/16 = 3000
Director
Joined: 27 Jun 2005
Posts: 513
Location: MS
Followers: 2

Kudos [?]: 36 [0], given: 0

1500

X6/16 -X4/16 =600 ==> X = 4800
5/16*4800 = 1500
SVP
Joined: 16 Oct 2003
Posts: 1813
Followers: 4

Kudos [?]: 56 [0], given: 0

hkm_gmat wrote:
Should be 3000

5X/16 - 4X/16 = 600

X/16 = 600

5X/16 = 3000

You have used second years depreicated amount. we have to use first year's.

I get 1800 1500 and 1200 as the depreciated amonuts. Answer is 1500.
Manager
Joined: 24 Oct 2005
Posts: 52
Followers: 1

Kudos [?]: 5 [0], given: 0

Got 1500 as well

Working is simple,

6x/16 - 4x/16 = 600, gives x = 4800

Now we need to find second year's depreciation, i.e 5x/16 = 1500
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