PS-Phoenix flight : PS Archive
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# PS-Phoenix flight

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Manager
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09 Sep 2004, 10:55
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Hi folks,

this is from the gmat challenge6.. I hope this is the right forum for posting a doubt on such a question.

The first flight out of phoenix on sunday was late. If the following three flights departed on time, what is the least number of flights that need to depart of time to reach more than 90% on time departure rate.

1) 6
2) 7
3) 9
4) 10
5) 11

My doubt: don't we need the number of flights scheduled for departure that day, to find the ans?
Director
Joined: 08 Jul 2004
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09 Sep 2004, 12:10
It is A.
1/(4+x) >9/10, gives 3 as least value. so total number of flight to depart on time is 6.
Let me know what do you feel.
S
Joined: 31 Dec 1969
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09 Sep 2004, 12:16
My guess is B as well. If the next 6 flights were on time that means that 9 out of ten flights left on time. The questions asks for more than 90 you need seven to get to 10 out of 11.
Joined: 31 Dec 1969
Location: Russian Federation
Concentration: Technology, Entrepreneurship
GMAT 1: 710 Q49 V0
GMAT 2: 700 Q V
GMAT 3: 740 Q40 V50
GMAT 4: 700 Q48 V38
GMAT 5: 710 Q45 V41
GMAT 6: 680 Q47 V36
GMAT 7: Q42 V44
GMAT 8: Q42 V44
GMAT 9: 740 Q49 V42
GMAT 10: 740 Q V
GMAT 11: 500 Q47 V33
GMAT 12: 670 Q V
WE: Engineering (Manufacturing)
Followers: 0

Kudos [?]: 199 [0], given: 102107

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09 Sep 2004, 12:22
90% = 9/10.

We have 1 delayed, 3 on time. Meaning the present ratio is 3/4 or 75%. This has to go up so,

(3+X)/(4+X) = 9/10

=>X=6

6 is still not good enough, because it just gets it to 90%, we need more than 90. So, 7. Ans. is B.
Director
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09 Sep 2004, 12:28
Sorry, I made the mistake, equation should be
3+x/4+x > 9/10
x>6, so 7, additional flights are minimum, therefore required number is 10.
S
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09 Sep 2004, 19:20
Anonymous wrote:
90% = 9/10.

We have 1 delayed, 3 on time. Meaning the present ratio is 3/4 or 75%. This has to go up so,

(3+X)/(4+X) = 9/10

=>X=6

6 is still not good enough, because it just gets it to 90%, we need more than 90. So, 7. Ans. is B.

OA is B - nice explanation. Thanks!
09 Sep 2004, 19:20
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