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PS: Pool 2

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Director
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Joined: 01 Apr 2008
Posts: 909
Schools: IIM Lucknow (IPMX) - Class of 2014
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Kudos [?]: 231 [0], given: 18

PS: Pool 2 [#permalink] New post 01 Apr 2009, 11:07
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A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

100% (04:16) correct 0% (00:00) wrong based on 3 sessions
With both valves open, the pool will be filled with water in 48 minutes. The first valve alone would fill the pool in 2 hours. What is the capacity of the pool if every minute the second valve admits 50 cubic meters of water more than the first?
* 9000 cubic meters
* 10500 cubic meters
* 11750 cubic meters
* 12000 cubic meters
* 12500 cubic meters
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Joined: 13 Jan 2009
Posts: 374
Location: India
Followers: 19

Kudos [?]: 66 [0], given: 1

Re: PS: Pool 2 [#permalink] New post 01 Apr 2009, 15:12
A fills tank in 120 mins.
A+B fill in 48 mins
So, B fills in 80 mins. ( A*T/A-T)

Let x be the capacity.

A will in one min x/120
B will in one min x/80


Now X/80 - x/120 = 50

So x is 12000

D.
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Joined: 28 Feb 2010
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Re: PS: Pool 2 [#permalink] New post 30 Mar 2010, 20:30
can you Explain how did you get the min of B?
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Re: PS: Pool 2 [#permalink] New post 31 Mar 2010, 13:30
First valve allows=x cubic meter/min
Second valve allows=x+50 cubic meter/min
total capacity=48(x+x+50)
and total capacity as well=120x

so 48(2x+50)=120x
x=100
and capacity 120*100=12000 cubic meter
Intern
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Re: PS: Pool 2 [#permalink] New post 31 Mar 2010, 13:33
saqibbaig wrote:
First valve allows=x cubic meter/min
Second valve allows=x+50 cubic meter/min
total capacity=48(x+x+50)
and total capacity as well=120x

so 48(2x+50)=120x
x=100
and capacity 120*100=12000 cubic meter


ThankSSSS.perfect
Re: PS: Pool 2   [#permalink] 31 Mar 2010, 13:33
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PS: Pool 2

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