Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A Necklace is made by stringing N individual beads together in the repeating pattern red bead, green bead, white bead, blue bead, and yellow bead. If the necklace design begins with a red bead and ends with a white bead, then N could equal

is the answer D-68. i don't think there is a way of solving this. you have to check every answer.

there are 5 different color of beads , so 13 times these beads can be repeated in order. that gives 13*5=65, the remaining 3 will be red, green and the last will be white bead.

pattern is 5 beads long, if it starts on red and ends on white, then it must be 5x+3 so if x is odd then we have a 8, even, then we have a 3....68 is the only matching choice

pattern is 5 beads long, if it starts on red and ends on white, then it must be 5x+3 so if x is odd then we have a 8, even, then we have a 3....68 is the only matching choice

pattern is 5 beads long, if it starts on red and ends on white, then it must be 5x+3 so if x is odd then we have a 8, even, then we have a 3....68 is the only matching choice

sprtgn: Can you explain in detail how it is 5x+3

OA: E) 68

because it says that "If the necklace design begins with a red bead and ends with a white bead" red is the first bead in the pattern, and white is the third bead.

(for short, red bead (r), green bead(g), white bead(w), blue bead(b), and yellow bead(y) so for example, the design could be: r g w b y r g w = starts with red, ends with white, in this design, it has completed the pattern (r ~ y) once, which contains 5 beads, then the extra unfinished pattern which starts with read ends with w gives us 3.

so lets say...the design could be the pattern repeated 6 times ( 30 beads) before it stopped, because the design can't stop on a yellow, which is the last of the pattern, then it has to go on until it reaches white, which is that extra 3 beads, then we have 5*6 + 3...and so forth....which gives us 5 * x (however many times the pattern has repeated, could also be zero), and that extra 3 bead in order to get to white bead (read, green, white) to finish the design off. ... a little messy, let me know if it's still unclear!

because it says that "If the necklace design begins with a red bead and ends with a white bead" red is the first bead in the pattern, and white is the third bead.

(for short, red bead (r), green bead(g), white bead(w), blue bead(b), and yellow bead(y) so for example, the design could be: r g w b y r g w = starts with red, ends with white, in this design, it has completed the pattern (r ~ y) once, which contains 5 beads, then the extra unfinished pattern which starts with read ends with w gives us 3.

so lets say...the design could be the pattern repeated 6 times ( 30 beads) before it stopped, because the design can't stop on a yellow, which is the last of the pattern, then it has to go on until it reaches white, which is that extra 3 beads, then we have 5*6 + 3...and so forth....which gives us 5 * x (however many times the pattern has repeated, could also be zero), and that extra 3 bead in order to get to white bead (read, green, white) to finish the design off. ... a little messy, let me know if it's still unclear!