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pn
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68 for me as well.

pattern is 5 beads long, if it starts on red and ends on white, then it must be 5x+3 so if x is odd then we have a 8, even, then we have a 3....68 is the only matching choice
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sprtng
68 for me as well.

pattern is 5 beads long, if it starts on red and ends on white, then it must be 5x+3 so if x is odd then we have a 8, even, then we have a 3....68 is the only matching choice

sprtgn: Can you explain in detail how it is 5x+3

OA: E) 68
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E.

The answer must be a number that ends in 3 or 8.
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pn
sprtng
68 for me as well.

pattern is 5 beads long, if it starts on red and ends on white, then it must be 5x+3 so if x is odd then we have a 8, even, then we have a 3....68 is the only matching choice

sprtgn: Can you explain in detail how it is 5x+3

OA: E) 68

because it says that "If the necklace design begins with a red bead and ends with a white bead" red is the first bead in the pattern, and white is the third bead.

(for short, red bead (r), green bead(g), white bead(w), blue bead(b), and yellow bead(y)
so for example, the design could be: r g w b y r g w = starts with red, ends with white, in this design, it has completed the pattern (r ~ y) once, which contains 5 beads, then the extra unfinished pattern which starts with read ends with w gives us 3.

so lets say...the design could be the pattern repeated 6 times ( 30 beads) before it stopped, because the design can't stop on a yellow, which is the last of the pattern, then it has to go on until it reaches white, which is that extra 3 beads, then we have 5*6 + 3...and so forth....which gives us 5 * x (however many times the pattern has repeated, could also be zero), and that extra 3 bead in order to get to white bead (read, green, white) to finish the design off. ... a little messy, let me know if it's still unclear!
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sprtng

because it says that "If the necklace design begins with a red bead and ends with a white bead" red is the first bead in the pattern, and white is the third bead.

(for short, red bead (r), green bead(g), white bead(w), blue bead(b), and yellow bead(y)
so for example, the design could be: r g w b y r g w = starts with red, ends with white, in this design, it has completed the pattern (r ~ y) once, which contains 5 beads, then the extra unfinished pattern which starts with read ends with w gives us 3.

so lets say...the design could be the pattern repeated 6 times ( 30 beads) before it stopped, because the design can't stop on a yellow, which is the last of the pattern, then it has to go on until it reaches white, which is that extra 3 beads, then we have 5*6 + 3...and so forth....which gives us 5 * x (however many times the pattern has repeated, could also be zero), and that extra 3 bead in order to get to white bead (read, green, white) to finish the design off. ... a little messy, let me know if it's still unclear!


Thanks sprtng, its clear now :-D
Thanks Everyone
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E

68 is the only multiple of 5 +3



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