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Sqare Root Property

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Sqare Root Property [#permalink] New post 09 Apr 2012, 08:33
([square_root 10] + [square_root 10][/square_root 2]) ^2

why can't it be ([square_root 10][/square root 2)^2 + ([square_root 10][/square root 2)^2
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Re: Sqare Root Property [#permalink] New post 09 Apr 2012, 09:08
Thanks for the explanation! I needed that too :)

Maybe this will help: (sqr = square root)

[sqr 10 + sqr 10 / sqr 2 ] ^ 2

Can you explain why below is incorrect?

=> [sqr 10 / sqr 2]^2 + [sqr 10 / sqr 2]^2

=> 5 + 5 = 10

but the OA is 20
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Re: Sqare Root Property [#permalink] New post 11 Apr 2012, 09:26
Expert's post
catty2004 wrote:
([square_root 10] + [square_root 10][/square_root 2]) ^2

why can't it be ([square_root 10][/square root 2)^2 + ([square_root 10][/square root 2)^2


Go to algebra section of khanacademy.org and check out videos on 'Simplifying Radicals' there. They should help you understand how to deal with such questions.
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Re: Sqare Root Property [#permalink] New post 11 Apr 2012, 10:42
Either I'm reading this wrong or I need help with this also.

The question is [sqr 10 + sqr 10 / sqr 2 ] ^ 2

I'm reading this as (sqrt(10) + sqrt(5))^2 (The denominator is only under the second sqrt(10))

After factoring I'm getting 15 + 2sqrt(50)

Now if the denominator (sqrt(2)) is spanned across the entire numerator the problem becomes (2sqrt(5))^2 = 20
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Re: Sqare Root Property [#permalink] New post 11 Apr 2012, 10:53
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ashish8 wrote:
Either I'm reading this wrong or I need help with this also.

The question is [sqr 10 + sqr 10 / sqr 2 ] ^ 2

I'm reading this as (sqrt(10) + sqrt(5))^2 (The denominator is only under the second sqrt(10))

After factoring I'm getting 15 + 2sqrt(50)

Now if the denominator (sqrt(2)) is spanned across the entire numerator the problem becomes (2sqrt(5))^2 = 20


Here is the question with a solution; (\frac{\sqrt{10}+\sqrt{10}}{\sqrt{2}})^2=(\frac{2\sqrt{10}}{\sqrt{2}})^2=\frac{4*10}{2}=20.
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Re: Sqare Root Property   [#permalink] 11 Apr 2012, 10:53
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