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The variable x takes on integer values between 1 and 7 inclu [#permalink]
 08 Jan 2013, 21:25
Question Stats:
65% (02:14) correct
34% (01:04) wrong based on 2 sessions
X frequency 1 3 2 1 3 3 4 1 5 3 6 1 7 3 The variable x takes on integer values between 1 and 7 inclusive as shown above. What is the probability that the absolute value of the difference between the mean of the distribution which is 4 and a randomly chosen value of x will be greater than 3/2? A) 8/15 B) 4/7 C) 4/5 D) 6/7 E) 8/7
Last edited by fozzzy on 09 Jan 2013, 03:43, edited 1 time in total.
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Re: The variable X takes on integer values [#permalink]
08 Jan 2013, 22:26
The set is 1,1,1,2,3,3,3,4,5,5,5,6,7,7,7 The question basically asks for the probability of choosing 1,2,6 or 7. = 8/15
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Re: The variable X takes on integer values [#permalink]
08 Jan 2013, 22:47
MacFauz wrote: The set is
1,1,1,2,3,3,3,4,5,5,5,6,7,7,7
The question basically asks for the probability of choosing 1,2,6 or 7.
= 8/15 Hi Can you please explain in detail? how u got the values of set?
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Re: The variable X takes on integer values [#permalink]
08 Jan 2013, 22:58
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bhavinshah5685 wrote: MacFauz wrote: The set is
1,1,1,2,3,3,3,4,5,5,5,6,7,7,7
The question basically asks for the probability of choosing 1,2,6 or 7.
= 8/15 Hi Can you please explain in detail? how u got the values of set? Looking at the table., The column on the left shows the value of X and the column on the right shows the number of times the value appears. The question statement is just beating around the bush a lot to ask a simple question. What is the probability that 4 - X > 1.5. For such a case, X has to be 1,2,6 or 7.
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Re: The variable X takes on integer values [#permalink]
09 Jan 2013, 20:47
MacFauz wrote: bhavinshah5685 wrote: MacFauz wrote: The set is
1,1,1,2,3,3,3,4,5,5,5,6,7,7,7
The question basically asks for the probability of choosing 1,2,6 or 7.
= 8/15 Hi Can you please explain in detail? how u got the values of set? Looking at the table., The column on the left shows the value of X and the column on the right shows the number of times the value appears. The question statement is just beating around the bush a lot to ask a simple question. What is the probability that 4 - X > 1.5. For such a case, X has to be 1,2,6 or 7. Hi MacFauz, I guess answer is correct but the solution seems to be different to me. Pls correct me! given absolute difference is |4-X| >1.5so -1.5> |4-X| >1.5solving this 2.5 < X < 6.5This gives range from 3,3,3,4,5,5,5,6 Anyways, answer will be 8/15. Actually i did this wrong. On seeing ur solution i got it 
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Re: The variable X takes on integer values [#permalink]
09 Jan 2013, 21:27
shanmugamgsn wrote: MacFauz wrote: bhavinshah5685 wrote: The set is
1,1,1,2,3,3,3,4,5,5,5,6,7,7,7
The question basically asks for the probability of choosing 1,2,6 or 7.
= 8/15
Hi Can you please explain in detail?
how u got the values of set? Looking at the table., The column on the left shows the value of X and the column on the right shows the number of times the value appears. The question statement is just beating around the bush a lot to ask a simple question. What is the probability that 4 - X > 1.5. For such a case, X has to be 1,2,6 or 7. Hi MacFauz, I guess answer is correct but the solution seems to be different to me. Pls correct me! given absolute difference is |4-X| >1.5so -1.5> |4-X| >1.5solving this 2.5 < X < 6.5This gives range from 3,3,3,4,5,5,5,6 Anyways, answer will be 8/15. Actually i did this wrong. On seeing ur solution i got it The step in red is incorrect. You should note that the least value that |4-X| can take is 0. So, it can never be less than -1.5. The inequality should actually be X<2.5 or X>5.5.
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Re: The variable X takes on integer values [#permalink]
09 Jan 2013, 22:53
Actually it should be -1.5> 4-X >1.5 (it was a typo above) But still i didnt get u! |4-X| can be zero ? then |4-X|>1.5 will be 0>1.5This isnt wrong? Messed up  Pls explain
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Re: The variable X takes on integer values [#permalink]
09 Jan 2013, 22:58
shanmugamgsn wrote: Actually it should be -1.5> 4-X >1.5 (it was a typo above) But still i didnt get u! |4-X| can be zero ? then |4-X|>1.5 will be 0>1.5This isnt wrong? Messed up Pls explain I guess I wasn't clear. What I meant to say was that a modulus value cannot be negative. Of course in this question, we want only values for which |4-X|>1.5. The range that you have given (-1.5> 4-X >1.5) is not a valid one. A number cannot be both greater than 1.5 and lesser than -1.5. Rather the interval should be 1.5 < 4-X OR 4-X < -1.5
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Re: The variable X takes on integer values [#permalink]
10 Jan 2013, 20:05
MacFauz wrote: shanmugamgsn wrote: Actually it should be -1.5> 4-X >1.5 (it was a typo above) But still i didnt get u! |4-X| can be zero ? then |4-X|>1.5 will be 0>1.5This isnt wrong? Messed up Pls explain I guess I wasn't clear. What I meant to say was that a modulus value cannot be negative. Of course in this question, we want only values for which |4-X|>1.5. The range that you have given (-1.5> 4-X >1.5) is not a valid one. A number cannot be both greater than 1.5 and lesser than -1.5. Rather the interval should be 1.5 < 4-X OR 4-X < -1.5 Thanks MacFauz... ya i got my mistake in Inequalities. Thanks dude...
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The variable x takes on integer [#permalink]
29 Mar 2013, 00:32
need explanation of the attached file
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Re: The variable x takes on integer [#permalink]
29 Mar 2013, 00:51
x has values between 1 and 7 so |4-x|>\frac{3}{2}= |4-1|=3>3/2|4-2|=2>3/2|4-3|=1>3/2
|4-4|=0>3/2
|4-5|=1>3/2|4-6|=2>3/2|4-7|=3>3/2The value that respect |4-x|>3/2 are 1,2,6,7 that have a frequency of 3,1,1,3 so 3+1+1+3 = total frequencies of "right" events, and this will be our numerator. Our denominator will be the tot number of combinations = 3+1+3+1+3+1+3= 15.Answer \frac{8}{15}
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Re: The variable x takes on integer [#permalink]
29 Mar 2013, 02:20
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Re: The variable x takes on integer
[#permalink]
29 Mar 2013, 02:20
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