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I didn't get it.
AN isosceles triangle has two sides equal and one side that is either bigger or smaller.
(I) Gives the two different sides. It should be sufficient to answer the difference between two unequal sides.
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tsraeroshad
I didn't get it.
AN isosceles triangle has two sides equal and one side that is either bigger or smaller.
(I) Gives the two different sides. It should be sufficient to answer the difference between two unequal sides.

How do you know which side it is equal to?

PR, QR and PQ are the three sides.
PR > PQ so these are not the equal sides. So QR is one of the equal sides. But which side is it equal to? Is QR = PR or is QR = PQ? We don't know.

Using statement 1, we know that we can get two isosceles triangles:

If QR = PQ, then the triangle has sides in the ratio 1: 1: sqrt(2) (a right isosceles triangle)

If QR = PR, then the triangle has sides in the ratio 1: sqrt(2) : sqrt(2) (NOT a right triangle, but nevertheless isosceles)

They are playing on your familiarity with a 45-45-90 triangle and hoping that you will jump to that and forget that another case is possible.

Statement 2 tells us that angle P = angle R so QR = PQ and hence the triangle has sides 1: 1: sqrt(2) and area of (1/2)*leg*leg = 18 so each leg length is 6.
Length of hypotenuse then is 6*sqrt(2) and the difference between them is 6*sqrt(2) - 6

We don't need to do all this calculation at the end.

Answer (C)
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