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Updated on: 27 Jan 2024, 09:16
Originally posted by nomnomdumbb on 16 Nov 2023, 03:50.
Last edited by nomnomdumbb on 27 Jan 2024, 09:16, edited 1 time in total.
Last edited by nomnomdumbb on 27 Jan 2024, 09:16, edited 1 time in total.
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A group of runners start a race simultaneously on a circular track of 1000 meters. Runner A can complete a lap in 250 seconds, while runner B can complete a lap in 200 seconds. How many times will they meet at the starting point before runner B finishes 10 laps?
A. 2 times
B. 4 times
C. 5 times
D. 6 times
E. 7 times
A. 2 times
B. 4 times
C. 5 times
D. 6 times
E. 7 times
16 Nov 2023, 19:12
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nomnomdumbb
The time taken to meet at the starting point is the least common multiple (LCM) of individual lap times.
LCM(250, 200) = 1000 seconds
This means the runners will meet every 1000 seconds.
Number of meetings = Total time before B finishes 10 laps / Time for each meeting
The total time for 10 laps by runner B is: 2000 seconds
Number of meetings = 2000 / 1000 = 2 times
Shouldn't the answer be 2 times
General Discussion
23 Nov 2023, 00:56
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Answer should be 2 or even 3 if youre counting the starting.
lets say im ringing bell A every 2 seconds, and someone else is ringing bell B every 3 seconds. The only time both bells would ever ring together is when the time would be a multiple of 2 and 3, i.e LCM (2,3) = 6
Same though process: A takes 250 s to reach starting point and B takes 200 s
They'd meet each other only at LCM(200,250)=1000 seconds
B takes 2000 seconds (200x10) to complete 10 laps
number of times they'd meet = 2000/1000 = 2.
lets say im ringing bell A every 2 seconds, and someone else is ringing bell B every 3 seconds. The only time both bells would ever ring together is when the time would be a multiple of 2 and 3, i.e LCM (2,3) = 6
Same though process: A takes 250 s to reach starting point and B takes 200 s
They'd meet each other only at LCM(200,250)=1000 seconds
B takes 2000 seconds (200x10) to complete 10 laps
number of times they'd meet = 2000/1000 = 2.
