Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 1912:30 PM EST
-01:30 PM EST
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more
Nov 2001:30 PM EST
-02:30 PM IST
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2407:00 PM PST
-08:00 PM PST
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
01 May 2024, 10:37
Kudos
Bookmarks
Max A-B: 26
Max B: 32
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
33% (03:47) correct
67%
(03:46)
wrong
based on 218
sessions
History
Date
Time
Result
Not Attempted Yet
The class teacher divided 100 pencils amongst five students, A, B, C, D and E. The number of pencils received by A is equal to the sum of the pencils received by the three students, C, D and E. It is also known \(a \geq b \geq c\geq d \geq e\), where a, b, c, d and e are pencils received by A, B, C, D and E respectively.
On the basis of the information provided, select for Max A-B, the maximum difference between the number of the pencils received by A and the number of the pencils received by B, and select for Max B the largest number of the pencils that B could have got. Make only two selections, one in each column.
On the basis of the information provided, select for Max A-B, the maximum difference between the number of the pencils received by A and the number of the pencils received by B, and select for Max B the largest number of the pencils that B could have got. Make only two selections, one in each column.
| Max A-B | Max B | |
| 25 | ||
| 26 | ||
| 28 | ||
| 32 | ||
| 33 | ||
| 34 |
ShowHide Answer
Official Answer
Max A-B: 26
Max B: 32
02 May 2024, 06:53
Kudos
Bookmarks
chetan2u
We know a = c+d+e, and a+b+c+d+e = 100 or a+b+a = 100, that is 2a+b=100
Max A-B: We are looking into the difference of the two largest numbers, that is a-b. To make it the largest, we have to make a the largest possible and b the smallest possible.
The smallest value of b will be when it is equal to c, and c is also least possible.
Now, c+d+e = a
For c to be least, let it be equal to d and e, so c+c+c = a or \(c=\frac{a}{3}\).
Therefore, a+b+(c+d+e) = 100 or a+c+(a) = 100..........\(2a+\frac{a}{3}=100.......7a=300.....a=42.89\)
As a is an integer, the maximum value of a is 42.
Value of b = 42+b+42 = 100.......b=16
Max A-B = 42-16 = 26
Max B: We know 2a+b = 100, so to get maximum value of b, we have to minimize a.
Let b be equal to a, then 3a = 100 and a = 33.33
If a = 33, then b becomes 100-2*33 or 34, making b>a.
So a = 34, and b = 100-2*34 or 32.
General Discussion
anish777
Joined: 18 Feb 2021
Last visit: 09 Jan 2025
Posts: 108
Own Kudos:
Given Kudos: 143
Location: India
Schools: IIM Calcutta '26
GMAT Focus 1: 635 Q88 V79 DI77 
GPA: 7.98
03 May 2024, 04:56
Kudos
Bookmarks
Hi chetan2u
2A+B = 100
lets assume A-B = 32
Then A=B+32
2(B+32) + B = 100
3B = 36 => B=12
why is this not possible ?
2A+B = 100
lets assume A-B = 32
Then A=B+32
2(B+32) + B = 100
3B = 36 => B=12
why is this not possible ?
