Bunuel
A group of people is seated at a table at which a toast is made. Following the toast, each person must clink glasses exactly once with each of the other people at the table. If each clink is produced by the glasses of only two people, how many people are seated at the table?
(1) If two fewer people were seated at the table, there would be at least 17 but no more than 19 fewer clinks.
(2) If two more people were seated at the table, there would be at least 18 but no more than 21 fewer clinks.
Let n people are there, and nC2 is the number of clinks, that is the number of ways to choose two out of n people.
1) If two fewer people were seated at the table, there would be at least 17 but no more than 19 fewer clinks.
Now, the number of people is (n-2) and number of clinks = (n-2)C2
Thus, nC2-(n-2)C2 is 17, 18 or 19.
\(\frac{n(n-1)}{2} - \frac{(n-2)(n-3)}{2} = \frac{n^2-n+n^2+5n-6}{2} = 2n-3\)
\(2n-3=17…n=10\)
\(2n-3=18\)…n cannot be fraction
\(2n-3=19…n=11\)
Insufficient
(2) If two more people were seated at the table, there would be at least 18 but no more than 21 fewer clinks.
Now, the number of people is (n+2) and number of clinks = (n+2)C2
Thus, (n+2)C2 is 18, 19, 20 or 21
\(\frac{(n+2)(n+1)}{2} - \frac{(n-1)(n)}{2} = \frac{n^2+3n+2-n^2-n}{2} = 2n+1\)
\(2n+1=18\)… n cannot be fraction
\(2n+1=19…n=9\)
\(2n+1=20\)… n cannot be fraction
\(2n+1=21…n=10\)
Insufficient
Combined
n=10
sufficient
C
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