Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 1912:30 PM EST
-01:30 PM EST
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more
Nov 2001:30 PM EST
-02:30 PM IST
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2407:00 PM PST
-08:00 PM PST
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
27 Jun 2024, 01:30
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
30% (02:53) correct
70%
(02:20)
wrong
based on 280
sessions
History
Date
Time
Result
Not Attempted Yet
There are three different ways to score in basketball. A successful shot from beyond an arc drawn on the court is worth 3 points. Shots made from inside the arc are worth 2 points. If a player is fouled by another player, the fouled player may shoot "free throws," which are worth 1 point each. A certain team scored 45 points in a game. The team made twice as many 2-point shots as 3-point shots. How many free throws did the team make?
(1) The team attempted 12 free throws.
(2) Five-sixths of the team's free-throw attempts were successful.
(1) The team attempted 12 free throws.
(2) Five-sixths of the team's free-throw attempts were successful.
27 Jun 2024, 05:34
Kudos
Bookmarks
Let the number of one-pointers = \(x\), the number of two-pointers = \(y\) and the number of three-pointers = \(z\)
\(x+2y+3z = 45\)
We are told "The team made twice as many 2-point shots as 3-point shots". That means \(y = 2z\). Plugging that back in:
\(x+2(2z)+3z = 45\)
\(x+7z = 45\)
(1) The team attempted 12 free throws.
The team could have missed all of them, made all of them or made any number inbetween.
INSUFFICIENT
(2) Five-sixths of the team's free-throw attempts were successful.
This tells us that the number of freethrows that went in is a multiple of 5. This means that the value's unit digit will be either 0 or 5.
Looking at \(x+7z = 45\), as \(x\) will end in either 0 or 5, \(7z\) will have to end in the opposite value to ensure we have a units digit of 5.
The first number where \(7z\) will end in 0, is when \(z\) is 10 (\(7(10) = 70\). This obviously cannot hold as this is well above the 45 points scored, and the game does not have negative points. Therefore, \(7z\) needs to end in 5. The first time that occurs is when \(z = 5\) (\(7(5) = 35\)) and the next will be \(z = 15\) (\(7(15) = 105\)), which once again exceeds 45. Therefore \(z = 5\)
\(x+35 = 45\)
\(x = 10\)
SUFFICIENT
ANSWER B
\(x+2y+3z = 45\)
We are told "The team made twice as many 2-point shots as 3-point shots". That means \(y = 2z\). Plugging that back in:
\(x+2(2z)+3z = 45\)
\(x+7z = 45\)
(1) The team attempted 12 free throws.
The team could have missed all of them, made all of them or made any number inbetween.
INSUFFICIENT
(2) Five-sixths of the team's free-throw attempts were successful.
This tells us that the number of freethrows that went in is a multiple of 5. This means that the value's unit digit will be either 0 or 5.
Looking at \(x+7z = 45\), as \(x\) will end in either 0 or 5, \(7z\) will have to end in the opposite value to ensure we have a units digit of 5.
The first number where \(7z\) will end in 0, is when \(z\) is 10 (\(7(10) = 70\). This obviously cannot hold as this is well above the 45 points scored, and the game does not have negative points. Therefore, \(7z\) needs to end in 5. The first time that occurs is when \(z = 5\) (\(7(5) = 35\)) and the next will be \(z = 15\) (\(7(15) = 105\)), which once again exceeds 45. Therefore \(z = 5\)
\(x+35 = 45\)
\(x = 10\)
SUFFICIENT
ANSWER B
General Discussion
27 Jun 2024, 02:11
Kudos
Bookmarks
2(2x)+3x+f=45
7x+f=45
S1
f<=12 (not every free throw will land a point)
x can be 5 or 6
Insufficient
S2
if 5/6 succesful but 5/6 of what ?
Insufficient
S1+2
5/6 of 12 succesful = 10 points
we also know that x is 5 so 5 3 pointers and 10 2 pointers
Hence C
7x+f=45
S1
f<=12 (not every free throw will land a point)
x can be 5 or 6
Insufficient
S2
if 5/6 succesful but 5/6 of what ?
Insufficient
S1+2
5/6 of 12 succesful = 10 points
we also know that x is 5 so 5 3 pointers and 10 2 pointers
Hence C
