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Bismuth83
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Hello Armaan209. I also used alligation for this problem. Can you please explain why did you take total weight of zinc as 50kgs in RO1 when its given that zinc is 34% of 50kgs, which works out as 17kgs
Armaan209
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hi

can you please explain this.
Armaan209
Here if the solution
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cheshire
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You take the complete weight of alloy A because you are adding pure zinc to it. Your goal is to create a harder alloy so you take the original alloy in its entirety, not just the zinc composition.
NoeticImbecile
Hello Armaan209. I also used alligation for this problem. Can you please explain why did you take total weight of zinc as 50kgs in RO1 when its given that zinc is 34% of 50kgs, which works out as 17kgs
Armaan209
Here if the solution
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    Mixing 50 kg of Mix A (34% Zn) with pure Zn (100% Zn) to get 50% Zn.
  • Cl=34%, Ch=100%, target Cm=50%.
  • Parts of high (pure Zn) = Cm−Cl=50−34=16
  • Parts of low (Mix A) = Ch−Cm=100−50=50
  • Ratio Zn : Mix A = 16:50=8:25
  • Since Mix A is fixed at 50 kg (that’s “25 parts”), one “part” = 50/25=2 kg → pure Zn = 8×2=16

    Mixing 50 kg of Mix A (34% Zn) with Mix B (60% Zn) to get 50% Zn.
  • Here “lower” is Mix A at 34%, “higher” is Mix B at 60%, target 50%.
  • Parts of Mix B (high) = 50−34=16
  • Parts of Mix A (low) = 60−50=10
  • Ratio B : A = 16:10=8:5
  • Mix A is 50 kg (“5 parts”), so one part = 50/5=10 kg → Mix B = 8×10=80 kg, which contributes 0.6×80=48 kg of Zn.

I assume you know how Alligation works (the process used above)? If you don't I would look up a more comprehensive explanation of the method rather than just this application as its useful in a lot of situations.

bibhuti750
hi

can you please explain this.
Armaan209
Here if the solution
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