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In some months last year, Natalie, a sales representative at SmithKlin

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Bunuel
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In some months last year, Natalie, a sales representative at SmithKlin [#permalink] New post   03 Oct 2019, 01:53
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24% (01:35) correct 76% (01:29) wrong based on 84 sessions
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In some months last year, Natalie, a sales representative at SmithKline & Beecham, went over $60000 in sales. In how many months last year did she do so?

(1) Last year, the number of months in which Natalie went over $60000 was 8 months more than the number of months in which she did not.

(2) Last year, the number of months in which Natalie went below $60000 was 1/5 the number of months in which she did not.
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DavidTutorexamPAL
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Re: In some months last year, Natalie, a sales representative at SmithKlin [#permalink] New post   03 Oct 2019, 02:14
Bunuel wrote:
In some months last year, Natalie, a sales representative at SmithKline & Beecham, went over $60000 in sales. In how many months last year did she do so?

(1) Last year, the number of months in which Natalie went over $60000 was 8 months more than the number of months in which she did not.

(2) Last year, the number of months in which Natalie went below $60000 was 1/5 the number of months in which she did not.


1) the important fact here is that the cases in which she did and did not go over are complementary. This means that if she didn't go over x months, and did x+8 months, then we know that
x + x + 8 = 12
2x =4
x = 2.
went over 2+8=10 months.
Sufficient!

2) using the same logic of before:
x + 5x = 12
6x=12
x=2
5x=10
sufficient!

answer D.
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satya2029
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Re: In some months last year, Natalie, a sales representative at SmithKlin [#permalink] New post   03 Oct 2019, 04:13
DavidTutorexamPAL wrote:
Bunuel wrote:
In some months last year, Natalie, a sales representative at SmithKline & Beecham, went over $60000 in sales. In how many months last year did she do so?

(1) Last year, the number of months in which Natalie went over $60000 was 8 months more than the number of months in which she did not.

(2) Last year, the number of months in which Natalie went below $60000 was 1/5 the number of months in which she did not.


1) the important fact here is that the cases in which she did and did not go over are complementary. This means that if she didn't go over x months, and did x+8 months, then we know that
x + x + 8 = 12
2x =4
x = 2.
went over 2+8=10 months.
Sufficient!

2) using the same logic of before:
x + 5x = 12
6x=12
x=2
5x=10
sufficient!

answer D.

I have a doubt here -
In 2)
could you please tell me how did you come to know that in those 5X months Natalie crossed $60000. How about sales=$60,000? We are asked about sales above $60000.
Thanks
SATYA
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DavidTutorexamPAL
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Re: In some months last year, Natalie, a sales representative at SmithKlin [#permalink] New post   03 Oct 2019, 04:54
satya2029 wrote:
DavidTutorexamPAL wrote:
Bunuel wrote:
In some months last year, Natalie, a sales representative at SmithKline & Beecham, went over $60000 in sales. In how many months last year did she do so?

(1) Last year, the number of months in which Natalie went over $60000 was 8 months more than the number of months in which she did not.

(2) Last year, the number of months in which Natalie went below $60000 was 1/5 the number of months in which she did not.


1) the important fact here is that the cases in which she did and did not go over are complementary. This means that if she didn't go over x months, and did x+8 months, then we know that
x + x + 8 = 12
2x =4
x = 2.
went over 2+8=10 months.
Sufficient!

2) using the same logic of before:
x + 5x = 12
6x=12
x=2
5x=10
sufficient!

answer D.

I have a doubt here -
In 2)
could you please tell me how did you come to know that in those 5X months Natalie crossed $60000. How about sales=$60,000? We are asked about sales above $60000.
Thanks
SATYA



we are told "the number of months in which Natalie went below $60000 was 1/5 the number of months in which she did not".
so if we call months not below x, then months below is 5x.
since there is a total of 12 months, we get the equation:
x+5x=12
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truplayer257
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Re: In some months last year, Natalie, a sales representative at SmithKlin [#permalink] New post   03 Oct 2019, 11:04
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satya2029 wrote:
DavidTutorexamPAL wrote:
Bunuel wrote:
In some months last year, Natalie, a sales representative at SmithKline & Beecham, went over $60000 in sales. In how many months last year did she do so?

(1) Last year, the number of months in which Natalie went over $60000 was 8 months more than the number of months in which she did not.

(2) Last year, the number of months in which Natalie went below $60000 was 1/5 the number of months in which she did not.


1) the important fact here is that the cases in which she did and did not go over are complementary. This means that if she didn't go over x months, and did x+8 months, then we know that
x + x + 8 = 12
2x =4
x = 2.
went over 2+8=10 months.
Sufficient!

2) using the same logic of before:
x + 5x = 12
6x=12
x=2
5x=10
sufficient!

answer D.

I have a doubt here -
In 2)
could you please tell me how did you come to know that in those 5X months Natalie crossed $60000. How about sales=$60,000? We are asked about sales above $60000.
Thanks
SATYA


I was thinking the same thing. Statement 2 would not be sufficient because of this.

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Henry_N_11
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Re: In some months last year, Natalie, a sales representative at SmithKlin [#permalink] New post   03 Mar 2024, 18:39
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This one is a bit controversial isn't it?
One could argue that there might be months in which sales EQUAL 60 k
this would change the problem because we would have the following equations:
equal + over + below = 12

1) o = (b+e)+8
2) b = (o+e)*1/5

In this case, (1) would be sufficient because we would have o + (o-8) = 12 => o = 10. But (2) alone would not be sufficient because we would only be able to find that b+5b=12 => b=2, but we would not be able to find o. So the correct answer is indeed (A) if we use this logic, and not (D) as some comments are suggesting.
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salilbagai
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Re: In some months last year, Natalie, a sales representative at SmithKlin [#permalink] New post   06 Mar 2024, 10:43
I think the question is absolutely correct. St 1 is sufficient and statement is not. Mathematics is simple here, its just the language nuances one needs to focus on.
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DebuBoss22
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Re: In some months last year, Natalie, a sales representative at SmithKlin [#permalink] New post   11 Mar 2024, 06:28
Doubt: What if Natalie was a new employee and didn't even work 12 months at SmithKline & Beecham? Hence I thought the answer would be E. As Statement 2 doesn't account for months where x=60000 so we can't come to a definite value of x using 2 equations either. Where is the error in my logic?
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Re: In some months last year, Natalie, a sales representative at SmithKlin [#permalink]
11 Mar 2024, 06:28
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Bunuel
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